Where is the image formed and what is its magnification?

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Homework Help Overview

The discussion revolves around a problem involving a convex lens, where an object is placed 10 cm in front of the lens with a focal length of 20 cm. Participants are exploring where the image is formed and what its magnification is, with a request for a ray diagram to accompany the solution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants reference the lens formula to find the image distance and discuss the implications of the negative sign in the result. Others question the understanding of the lens equation and its components. There is also mention of the magnification formula and its interpretation regarding image orientation.

Discussion Status

Participants are actively engaging with the problem, providing mathematical approaches and discussing the significance of the results. There is a mix of attempts to clarify concepts and explore the implications of the calculations, though no consensus has been reached on the final interpretation of the results.

Contextual Notes

Some participants emphasize the need for a ray diagram to aid in understanding the image formation, while others suggest reviewing foundational concepts related to the lens equation and magnification.

suf7
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Need Help With Lens!

An object is placed 10cm in front of a convex lens of focal length 20cm. Where is the image formed and what is its magnification??..Your solution should include an accurately drawn ray diagram?

Pleeez help me with this question?...im so stuck??

Thanks.
 
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Use the lens formula:

1/f = 1/u + 1/v

where f = focus, u = object distance from lens, and v = image distance from lens

So:

1/20 = 1/10 + 1/v

Solve for v
v = -20cm

So the image is located at 20cm
 
Last edited:
suf7 said:
An object is placed 10cm in front of a convex lens of focal length 20cm. Where is the image formed and what is its magnification??..Your solution should include an accurately drawn ray diagram?

Pleeez help me with this question?...im so stuck??

Thanks.

You should have at least[/b] be able to know where to start! The lens equation would have been a good one. If you didn't even know this, then you should review the material again and know what that equation is for, and how to use it.

If you do that, then you would have been able to derive what IntuitioN did, AND, be able to decipher what the "v = -20 cm" answer means (i.e. what does the NEGATIVE sign signifies). So look at the lens equation, and understand how each symbol are defined.

Zz.
 
IntuitioN said:
Use the lens formula:

1/f = 1/u + 1/v

where f = focus, u = object distance from lens, and v = image distance from lens

So:

1/20 = 1/10 + 1/v

Solve for v
v = -20cm

So the image is located at 20cm

oh right, thank you...so when i work out the magnification would it be 20/10 which is 2?
 
And for your ray diagram draw the lens with a compass. Then put in the object and draw the rays.
 
the ray diagram should have given you a clue to the image's location, magnification, and orientation. it is actually pretty easy.
 
magnification formula is [tex]m = - \frac{d_{i}}{d_{o}}[/tex]
where di is the image distance and do is the object distance and the negative sign means that if it was positive then the image is in the same direction as the object, if neaitve then the opposite direction.
thi DIRECTION means that if the object were an arrow poiting upward, then a negatie magniification would mean that the image arrow would point downwwward, signifying an inverted image
 

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