Magnification, when is it negative?

In summary, magnification can be positive or negative depending on the type of image (virtual or real) and the distance between the lens and the object. The sign convention for magnification is determined by the sign convention for distance, with negative values representing objects and images on the same side of the lens. This may lead to seemingly contradictory results for virtual images, but can be explained by considering the entire optical system, including the use of relay lenses.
  • #1
izMuted
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Homework Statement


In magnification, I keep on confusing the signs. From what I understand currently, magnification is positive when the image is erect. An image is only erect when it is a virtual image, therefore virtual images = positive magnification. Vice versa, magnification is negative when the image is inverted, therefore a real image.

However using the equation m = v/u, m is negative when v is negative. And v is only negative when the image is on the same side of the lens as the object. Therefore meaning a virtual image (According to physicsclassroom "The negative value for image distance indicates that the image is a virtual image located on the object's side of the lens."). This contradicts the statement above where virtual images = positive magnification.

Where am I going wrong?

Homework Equations


m = v/u

The Attempt at a Solution

 
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  • #2
izMuted said:
An image is only erect when it is a virtual image, therefore virtual images = positive magnification. Vice versa, magnification is negative when the image is inverted, therefore a real image.

That's only true for a single lens. A multi-element optical system can have positive magnification without the image being a virtual image. Consider a system which uses a relay lens. The objective generates an intermediate image which the relay lens then images, resulting in an upright final image of positive magnification. No virtual image necessary.

izMuted said:
However using the equation m = v/u, m is negative when v is negative.

Assuming u is the distance between the lens and the object, then sign convention dictates that it should be negative. If you imagine the lens to be at the origin of a graph, then the object is to the left of 0, which is the negative direction. A virtual image would also be to the left and would also have a negative value for distance. The negatives would cancel out and the magnification would be positive.
 
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1. What does it mean if a magnification is negative?

A negative magnification indicates that the image is inverted compared to the object, meaning that it appears upside down. This can happen when the object is placed beyond the focal point of a concave lens or in front of the focal point of a convex lens.

2. Is a negative magnification always bad?

No, a negative magnification is not necessarily bad. In fact, it is often desired in certain optical instruments such as microscopes and telescopes, where an inverted image is needed for proper viewing and analysis.

3. How is negative magnification different from positive magnification?

Negative magnification means the image is inverted, while positive magnification means the image is upright. Positive magnification is typical for a convex lens, while negative magnification is typical for a concave lens.

4. Can a magnification be both negative and positive?

No, a magnification can only be either negative or positive, depending on the position of the object and the type of lens. It cannot be both at the same time.

5. Why do we use negative magnification in some cases?

Negative magnification can be useful in certain applications where an inverted image is needed, such as in microscopes and telescopes. It also allows for more flexibility in the design of optical systems.

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