Finding Expectation Values & Expressing Eigenstates

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Discussion Overview

The discussion revolves around two main questions related to quantum mechanics: finding the expectation value of the x-component of angular momentum, \(\langle L_x \rangle\), given \(\langle L^2 \rangle\) and \(\langle L_z \rangle\); and expressing a quantum state \(|\Psi\rangle\) as a linear combination of the eigenstates of two different operators, A and B. The scope includes theoretical and mathematical reasoning within quantum mechanics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants suggest that \(\langle L_x \rangle\) cannot be determined solely from \(\langle L^2 \rangle\) and \(\langle L_z \rangle\) unless in an eigenstate of both operators.
  • Others propose that if in an eigenstate of \(L^2\) and \(L_z\), \(\langle L_x \rangle\) would be zero due to the cylindrical symmetry of these states.
  • One participant clarifies the notation used, distinguishing between angular momentum operators \(L\) and \(J\), and discusses the role of ladder operators in calculating expectation values.
  • Another participant raises concerns about the ambiguity in expressing a state in terms of different operator eigenstates, noting that eigenvectors are defined up to a complex factor.
  • There is a discussion about the mathematical representation of states in different bases and the implications of linear combinations of eigenstates.

Areas of Agreement / Disagreement

Participants express differing views on the determination of \(\langle L_x \rangle\) and the implications of eigenstate representations. The discussion remains unresolved regarding the exact method to express \(|\Psi\rangle\) in terms of the eigenstates of operator B.

Contextual Notes

There are limitations regarding the assumptions made about the states and operators involved, particularly concerning the definitions and properties of eigenstates and the implications of their linear combinations.

broegger
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Two quick ones :)

Hi, two questions:

1) How can I find the expectation value of the x-component of the angular momentum, [tex]\langle L_x \rangle[/tex], when I know [tex]\langle L^2 \rangle[/tex] and [tex]\langle L_z \rangle[/tex]?

2) Say, I have a state [tex]|\Psi \rangle[/tex] and two operators A and B represented as matrices. Now, [tex]|\Psi \rangle[/tex] is given as a linear combination of the eigenstates of A and I want to express them as a linear combination of the eigenstates of the operator B instead. How do I do that?

Thanks :)
 
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broegger said:
1) How can I find the expectation value of the x-component of the angular momentum, [tex]\langle L_x \rangle[/tex], when I know [tex]\langle L^2 \rangle[/tex] and [tex]\langle L_z \rangle[/tex]?

I don't think you can ! I think you can if you are in an EIGENSTATE of L^2 and Lz, but not if you only know the expectation values, because I think I can make up two different wave functions with same expectation for L^2 and Lz and different expectation for Lx...

cheers,
Patrick.
 
Oh, they ARE eigenstates of both L^2 and Lz. Sorry. What do I do? :)
 
broegger said:
Oh, they ARE eigenstates of both L^2 and Lz. Sorry. What do I do? :)

I think you will always find 0, no ? Because of the cylindrical symmetry of these states ?

The reason is that you can write Jx as 1/2 (J_+ + J_-) and these, acting on a state |j,m> will give you |j,m+1> and |j,m-1>, so
<j,m| Jx |j,m> = 0, no ?

cheers,
patrick.
 
I don't quite get it. What does the |J>'s represent?
 
broegger said:
I don't quite get it. What does the |J>'s represent?

Sorry, I should have written L. J stands in general for an angular momentum, L for an orbital angular momentum and S for a spin angular momentum. One usually uses the notation J if it doesn't matter (as is the case here) whether it is orbital or spin angular momentum one talks about.

I would think you are aware of J+ and J- (or L+ and L-), the ladder operators of angular momentum ?

cheers,
Patrick.
 
broegger said:
2) Say, I have a state [tex]|\Psi \rangle[/tex] and two operators A and B represented as matrices. Now, [tex]|\Psi \rangle[/tex] is given as a linear combination of the eigenstates of A and I want to express them as a linear combination of the eigenstates of the operator B instead. How do I do that?

I guess you mean that you work in a certain basis, in which you get to know the components of A (matrix) and B (matrix).
However, there is an ambiguity in the way you know psi: if you know its projections on the eigenvectors of A, you don't necessarily know its components in the basis in which A is given, because eigenvectors are only defined upto a complex multiplication factor ! So depending on how these eigenvectors were fixed your components will have an ambiguity (each of them individually) of a complex factor: just as well say that you don't know them (except if they happen to be 0).

Happily, you can hold the same reasoning for B :-) so I would say that a possible answer to the question will always be, that in a suitably scaled set of eigenvectors of B, psi will always take on the components {1,1,1,1,...1}
:redface:

cheers,
Patrick.
 
Sorry, I'm wasting your time. The situation in 1) is this:

An electron moving in a Coulomb-field from a proton, is in the following state (at time t=0)

[tex]|\phi,t=0> = \tfrac4{5}|100> + \tfrac{3i}5|211>[/tex]​

where [tex]|nlm>[/tex] is the usual energy eigenstates of the hydrogenatom. They are also eigenstates of angularmomentum:


[tex]L^2|nlm>=l(l+1)\hslash^2|nlm>[/tex]

[tex]L_z|nlm>=m\hslash|nlm>[/tex]

The questions are now:

a) Calculate the expectation value <E> in the state [tex]|\phi,t=0>[/tex].

b) Calculate the expectation values for L^2 and L_z in the state [tex]|\phi,t=0>[/tex].

c) Calculate the expectation value for L_x in the state [tex]|\phi,t=0>[/tex].

It's c) I'm having trouble with. Hope this helps.
 
Last edited:
[tex]\langle \hat{L}_{x}\rangle_{|\psi\rangle} =:\langle\psi|\hat{L}_{x}|\psi\rangle[/tex]

Okay?

Now,use the fact that

[tex]\hat{L}_{x}=\frac{1}{2}\left(\hat{L}_{+}+\hat{L}_{-}\right)[/tex]

and the action of [itex]\hat{\mbox{L}}_{+}[/itex] and [itex]\hat{\mbox{L}}_{-}[/itex] on an arbitrary hydrogenoid wavefunction [itex]|n,l,m\rangle[/itex] (see textbook) and the orthonormalization of the states

[tex]\langle n,l,m|n',l',m'\rangle =\delta_{nn'}\delta_{ll'}\delta_{mm'}[/tex]

Daniel.
 
  • #10
Yep, I with you now :) Thank you both.
 
  • #11
I assume that eigenvectors of both A and B provide the complete basis. (?)
well, about matrices

you have
|c>=|A><A|c>

you need to find

|c>=|B><B|c>

where |A> and |B> - eigenvectors

then

<b|c>=<B|A><A|c>;
 
  • #12
I don't follow.What and who are those A,B,a,b,,blah,blah,blah...?

Daniel.
 
  • #13
that is an old linear algebra in QM notation. I assume that eigenvectors of each matrix forms an ortogonal basis.

You have vector in the basis of the A matrix

[tex]\vec\psi=a_1 \vec{a_1}+a_2 \vec{a_2}+...[/tex] (1)

you need to find

[tex]\vec\psi=b_1 \vec{ b_1}+b_2 \vec{ b_2}+...[/tex] (2)

so multiply (1) by [tex]\vec{b_1}, \vec{b_2}...[/tex] and so on.

[tex]b_1 =a_1 (\vec {a_1}\vec{ b_1})+a_2 (\vec {a_1}\vec{ b_1})+...[/tex]
 
  • #14
Okay.What relevance does it have here?

Daniel.
 
  • #15
well,

Say, I have a state and two operators A and B represented as matrices. Now, [tex]\psi[/tex] is given as a linear combination of the eigenstates of A

that was (1)


and I want to express them as a linear combination of the eigenstates of the operator B instead.
that was (2)
 
  • #16
Are u hijacking the thread?This was the context

Two quick ones :)

--------------------------------------------------------------------------------

Hi, two questions:

1) How can I find the expectation value of the x-component of the angular momentum, , when I know and ?

2) Say, I have a state and two operators A and B represented as matrices. Now, is given as a linear combination of the eigenstates of A and I want to express them as a linear combination of the eigenstates of the operator B instead. How do I do that?

Thanks :)


[end quote]


Daniel.
 

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