Oentane is a liquid with a vapor pressure of 512 Torr at 25C

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SUMMARY

Oentane has a vapor pressure of 512 Torr at 25°C, while hexane has a vapor pressure of 151 Torr at the same temperature. To achieve equal amounts of pentane and hexane in the gas phase, Raoult's Law must be applied. The equation P = Ppure~hexaneChexane + Ppure~oentaneCoentane is essential for calculating the molar composition of the liquid phase. This approach allows for the determination of the necessary composition to balance the vapor pressures.

PREREQUISITES
  • Understanding of Raoult's Law
  • Knowledge of vapor pressure concepts
  • Familiarity with molar composition calculations
  • Basic principles of gas-liquid equilibrium
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  • Learn about gas-liquid equilibrium principles
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Oentane is a liquid with a vapor pressure of 512 Torr at 25C; at the same temperature, the vapor pressure of hexane is only 151 Torr. what composition must the liquid phase have if the gas hase composition is to have equal amounts of pentane and hexane?

Do I use p = i M R T to solve for the M, molar masses? How do I need to get started
 
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No, you'll need to use the Rault's law

[tex]P=P_{pure~hexane}C_{hexane}+P_{pure~oentane}C_{oentane}[/tex]

where C=molar composition of respective compound
 

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