Couple questions about complex integrals

Click For Summary

Discussion Overview

The discussion revolves around complex integrals in complex analysis, focusing on their geometric interpretation, the legality of indefinite integrals versus antiderivatives, and the dimensionality involved in representing complex functions. Participants express confusion and seek clarification on these concepts.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant expresses confusion about the lack of geometric interpretation for complex integrals and questions why indefinite integrals are considered 'illegal'.
  • Another participant suggests that a complex function of a complex variable requires representation in four dimensions, implying that this may relate to the difficulty in visualizing complex integrals.
  • There is a claim that the indefinite integral of a function can be computed regardless of whether the variable is real or complex, challenging the notion of illegality associated with indefinite integrals.
  • Some participants assert that indefinite integrals are indeed antiderivatives, while others mention that their teacher distinguishes between the two, suggesting that using 'indefinite integral' may lead to losing points.
  • A participant elaborates on the concept of four-dimensional geometry, attempting to explain how complex functions can be visualized through orthogonal axes and slices in higher dimensions.
  • Another participant raises a question about the geometric interpretation of an antiderivative on the graph of a function, indicating a desire for a more formal definition.

Areas of Agreement / Disagreement

Participants express differing views on the legality of indefinite integrals and their relationship to antiderivatives. There is no consensus on the geometric interpretation of complex integrals, and the discussion remains unresolved regarding the definitions and implications of these concepts.

Contextual Notes

Some participants mention that their understanding of indefinite integrals being undefined may depend on specific definitions or educational contexts, which could vary among instructors.

cAm
Messages
49
Reaction score
0
we recently started integrals over the complex plane, in complex analysis. But, I am confused on the iterpretation of some of it. From what I've heard/understand, there Is no geometrical interpretation of a complex integral. Why is this? Also, why is it 'illegal' to do an indefinate integral. What's the difference between doing that, and an antiderivative?
 
Physics news on Phys.org
small bump?
 
"From what I've heard/understand, there Is no geometrical interpretation of a complex integral. Why is this? Also, why is it 'illegal' to do an indefinate integral. "

I can't answer this because I've never heard either of those things. Certainly, a complex function of a complex variable would have to be represented in 4 dimensions. Perhaps that is what was meant- 4 dimension geometry is hard to imagine!
The indefinite integral of f(z)= 2z is z2+ C whether z is a real variable or complex. Nothing "illegal" about that!
 
HallsofIvy said:
"From what I've heard/understand, there Is no geometrical interpretation of a complex integral. Why is this? Also, why is it 'illegal' to do an indefinate integral. "

I can't answer this because I've never heard either of those things. Certainly, a complex function of a complex variable would have to be represented in 4 dimensions. Perhaps that is what was meant- 4 dimension geometry is hard to imagine!
The indefinite integral of f(z)= 2z is z2+ C whether z is a real variable or complex. Nothing "illegal" about that!


hmm... we've beent tought that indefinate integrals are undefined, though we can do antiderivatives.

And, do you know what the geometrical representation is, even if it is hard to conceptualize in 4d?
 
"hmm... we've beent tought that indefinate integrals are undefined, though we can do antiderivatives"

Indefinite integrals ARE anti-derivatives.
 
HallsofIvy said:
"hmm... we've beent tought that indefinate integrals are undefined, though we can do antiderivatives"

Indefinite integrals ARE anti-derivatives.


That's what i always thought, but my teacher is specifically saying that if we use an 'indefinate integral' then we'll lose some points. Whereas, an antiderivative is fine.
 
4d geometry is a good thinking exercise to try and visualise. Right, imagine a function that takes and returns a real number (ie it exists on the 'normal' number line). You can represent this as a line on a 2d graph, with aeis, say, x and y being at a [tex]90^\circ[/tex] angle to each other. In this 2 dimensional space, the axes x and y are said to be orthogonal - finding out the x position of a point gives you no information on the y position. You then extend this to three dimensions, we get the x, y and z axes. Again, knowledge of a point in 3D's position on one axis contains no information about the point's position on the other two axes - the three axes are again orthogonal.

Now think of this - you can project a 3D graph onto a 2D graph by taking a slice through at, say, a given Z value. For example, a sphere in 3d withh describe either nothing, a circle or a point when projected for a given 'slice' into 2D.

This all works nice and easy because we live in 3D. The conceptual leap comes when you consider 4 orthogonal axes. In a function taking and returning complex values we require 4 values to describe the function's behaviour:

[tex]f(z_{1}) = f(a+bi)= z_{2} = c+di[/tex]

Where [tex]z_{1,2}[/tex] are complex and a, b, c, d are real. These four numbers can represent four orthogonal axis, just as for f(x)=y, x and y represent values on two orthogonal axes.

Try to imagine slices through this 4D space. They will be able to be represented as 3D graphs that you can visualise.

I hope that helps - mull it over a bit.
 
Also, why is it 'illegal' to do an indefinate integral. What's the difference between doing that, and an antiderivative?

perhaps this question is in regard to the definition of the integral in the respect to Riemann sums. By the way, what would be the geometrical interpretation of a antiderivative F(a) on the graph of f(x)? I have an idea, but perhaps there's a more formal definition to this.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K