What is the Correct Calculation for the Inertia Tensor in a 2D Rotation?

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Homework Help Overview

The discussion revolves around the calculation of the inertia tensor in a 2D rotation context, specifically in the x-y plane. The original poster expresses confusion regarding the correct components of the inertia tensor and contrasts their calculations with those provided by their professor.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the components of the inertia tensor, questioning the accuracy of their calculations compared to their professor's. Participants raise questions about the significance of off-diagonal terms and the necessity of an orthogonal basis for the calculations. There is also a discussion about the implications of products of inertia and their relationship to angular momentum.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the inertia tensor's components and their implications. Some guidance has been offered regarding the importance of the full tensor for different rotational axes, but there is no explicit consensus on the correct approach or understanding of the products of inertia.

Contextual Notes

Participants note the absence of summation symbols in the original poster's calculations and question the assumptions underlying the definitions and components of the inertia tensor. There is an acknowledgment of the complexity introduced by using different bases for calculations.

CrusaderSean
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my homework problem deals w/ rotation in x-y plane. so the tensor is only 2d. inertial tensor still seems obscure to me... my question for now is purely mathematical. assuming the basis are (x,y). I calculated the components of I, is the following correct?
[tex]I_{xx} = m_i y_{i}^{2}[/tex]
[tex]I_{yy} = m_i x_{i}^{2}[/tex]
[tex]I_{xy} = I_{yx} = - m_i x_i y_i[/tex]

for some reason my professor wrote...
[tex]I_{xx} = m_i x_{i}^{2}[/tex]
and I'm pretty sure its not right
 
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You're fine (besides the missing summation symbols). Think of it this way: if you are rotating about the x-axis, would your inertia depend on where you are along the x-axis or how far away you are from the x-axis.
 
what about the off diagonal terms? are they moments about x=y line?... also do you need orthogonal basis for calculating inertial tensor? from the general definition it doesn't look like a requirement.
 
Sorry, I don't have a good analogy in mind for the products of inertia; maybe someone else reading the thread can help us out. I guess it comes into play when you have rotation that is not along one of the principal axes.
I suppose you could calculate the inertial tensor using a different basis, but wouldn't that just complicate the algebra(and unnecessarily at that)? I'm sorry if I haven't been much help.
 
The full tensor (diagonal and off diagonal terms) is important for rotations about any axis through the origin in the x.y plane, not just the y = x line. The tensor product of I with the angular velocity vector gives the angular momentum vector. When the angular velocity vector is along the x or y axes, the off diagonal terms do not contribute.
 
I can see why angular momentum is in same direction as angular velocity if object rotates about principal axes only. My textbook derives the inertia tensor through rotational kinetic energy calculation. I can see that it relates energy w/ velocity... but i don't understand in what way products of inertia describe the relationship... perhaps i just need to do some problems and see how it all works out.
 

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