Cross Products relation to area.

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    Area Cross Relation
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SUMMARY

The area of a parallelogram defined by two vectors, v1 and v2, is calculated using the formula ||v1 X v2||, which represents the magnitude of the cross product of the two vectors. This relationship is derived from the geometric interpretation of the cross product, where the area is equal to the base (|v2|) multiplied by the height (|v1|sin(θ)), with θ being the angle between the vectors. Understanding this concept is crucial for applying vector mathematics in physics and engineering contexts.

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"The area of a parallelogram spanned by two vectors, v1 and v2, is ||v1 X v2||."

Would someone help me understand why this is true?
 
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Imagine a paralllelogram, and imagine 2 vectors V1, and V2, which have a Theta angle between them. Now You know the magnitude or modulus of the resultant vector of the cross product is given by [itex]|V_{1}||V_{2}| \sin{\theta}[/itex], imagine V2 is a horizontal vector (only a component of x), so it will be a side of the parallelogram (the base), now imagine V1 is directed at a theta angle, if you do V1sin theta, you will get the height of the parallelogram, so base times height equals area.
 
ah. That makes a lot of sense. Thanks
(I kinda forgot about |v1||v2|sin(theta).. The things I don't see... :frown:)
 

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