What is the convergence status of the given sequence and series?

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Homework Help Overview

The discussion revolves around the convergence status of a given sequence and series defined by the formula An = 5n / (12n + 5). Participants are tasked with determining whether the sequence and series converge or diverge, and if convergent, to provide the limit or sum.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the convergence of the series and sequence, with one noting the absence of a common ratio in the series and questioning its divergence. Another participant confirms the limit of the sequence as n approaches infinity is 5/12.

Discussion Status

Some guidance has been provided regarding the relationship between the convergence of the sequence and the convergence of the series. There is an ongoing exploration of the implications of the sequence's limit on the series' convergence.

Contextual Notes

Participants express uncertainty about the convergence criteria for the series, particularly in relation to the behavior of the sequence as n approaches infinity.

ILoveBaseball
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[tex]An = \frac{5n}{12n+5}[/tex]

For both of the following answer blanks, decide whether the given sequence or series is convergent or divergent. If convergent, enter the limit (for a sequence) or the sum (for a series). If divergent, enter INF if it diverges to infinity, MINF if it diverges to minus infinity, or DIV otherwise.


a.) The series n=1 to infinity(i don't know how to make the 'sum of' sign)
(An) I'm having trouble with this one, there seems to be no 'common ratio', so does this mean it's divergent? [tex]A_1 = 5/17, A_2 = 10/29, A_3 = 15/41[/tex]

b.) the squence [tex]A_n[/tex]. well for this one as n-> infinity, the limit should be 5/12
 
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ILoveBaseball said:
[tex]An = \frac{5n}{12n+5}[/tex]

For both of the following answer blanks, decide whether the given sequence or series is convergent or divergent. If convergent, enter the limit (for a sequence) or the sum (for a series). If divergent, enter INF if it diverges to infinity, MINF if it diverges to minus infinity, or DIV otherwise.


a.) The series n=1 to infinity(i don't know how to make the 'sum of' sign)
(An) I'm having trouble with this one, there seems to be no 'common ratio', so does this mean it's divergent? [tex]A_1 = 5/17, A_2 = 10/29, A_3 = 15/41[/tex]

b.) the squence [tex]A_n[/tex]. well for this one as n-> infinity, the limit should be 5/12


Your b) looks good and should tell you the answer to a) What is 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 + 5/12 +. . .
 
If

[tex]A_n = \frac{5n}{12n+5}[/tex]

then

[tex]\lim_{n \rightarrow \infty} A_n = \lim_{n \rightarrow \infty} \frac{5}{12+5/n}[/tex]
[tex]=\frac{5}{12+(\lim_{n \rightarrow \infty} 5/n)} = 5/12[/tex]
 
Hint for a) In order for a series such as [itex]\Sigma_1^{\infinity}A_n[/itex] to converge, it is necessary that the sequence {An} converge to 0.
 

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