What Can We Infer About Vector w Given Its Relation to u and v?

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Homework Help Overview

The discussion revolves around the properties of vector w, defined as a linear combination of vectors u and v, specifically in the context of their independence or dependence. Participants explore implications of these relationships in vector spaces.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants examine the implications of vector independence and dependence on the properties of vector w. Questions arise about whether w can be zero and the definitions of coplanarity in different dimensional spaces.

Discussion Status

The discussion is active, with participants offering differing views on the definitions of coplanarity and the implications of vector relationships. Some guidance has been provided regarding the nature of linear combinations and the dimensionality of vector spaces.

Contextual Notes

There are conflicting interpretations regarding the dimensionality of vectors and their coplanarity, particularly in higher-dimensional spaces. Participants reference external texts and question the validity of certain statements made about vector relationships.

Nx2
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hi guys just want to clarify something...

If we are givin (vectors w u and v) w=au +bv what can we say about w
a) if u and v are independent?
b) if u an v are independent?

this is what i got so far.
a) w cannot be writtin as a scalar multiple of u and v and are therefore not coplanar.
b)w can be written as a scalar multiple of u and v and are therefor coplanar.

but i think there is more to it. I don't think my answer explains enough.

in a) can i say that w=0?... just trying to find more properties of w for a) and b)... any help would be appreciated. thnks.

- Tu
 
Last edited:
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No, w is coplanar with u and v by virtue of being a linear combination of them. What is true is that if u and v are independent, then w is not a multiple of one or the other and is not "co-linear" with either. If u and v are dependent, then one is a multiple of the other, w is a multiple of each, and w points in the same direction as both u and v (which are "co-linear" since they are dependent).
 
We should know that any two vectors in a N-Dimensional space where N>1 should be coplanar since Plane is 2-dimensional , that is, any of the 2 vectors should lie on the same plane.
 
Guppy said:
We should know that any two vectors in a N-Dimensional space where N>1 should be coplanar since Plane is 2-dimensional , that is, any of the 2 vectors should lie on the same plane.

what? I am pretty sure that's wrong dude, what about two vectors in three space? your thinking is limited to 2 dimensions or 2-space..BTW Nx2, does that happen to be in the Harcourt mathematics 12 geometry and discrete math textbook?
 
In order to define a plane (through the origin), you need two (linearly independent) vectors. So it doesn't make much sense to talk about two vectors being coplanar. Sure, they're always both in some plane together, though, specifically, the plane that they define (if they're independent)!
 
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MiniTank said:
what? I am pretty sure that's wrong dude, what about two vectors in three space? your thinking is limited to 2 dimensions or 2-space..BTW Nx2, does that happen to be in the Harcourt mathematics 12 geometry and discrete math textbook?

No, Guppy is completely correct and you are completely wrong. Any two vectors define either a line (if one is a multiple of the other) or a plane (if one is NOT a multiple of the other).
 
Questions of that form appear in numerous texts, MiniTank, though it would be odd if you were right.
 
HallsofIvy said:
No, Guppy is completely correct and you are completely wrong. Any two vectors define either a line (if one is a multiple of the other) or a plane (if one is NOT a multiple of the other).

ya your right. my mistake
 

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