Finding critical angles and index of refractions

[mark9159]

im having trouble setting my TI-83 Plus into "degree mode" so i can't seem to get the answers for these problems...im probably doing them wrong too

A material has an index of refraction of 1.75. What is the critical angle for this material?

Sin(critical angle)=1/n, n being the index of refraction
how would i set up the formula? (critical angle)= Sin(n) ?? I am so confused

and

The critical angle for cubic zirconium is 29.2º. What is the index of refraction?

so...Sin(29.2º)= 1/n?...

my answer for this question is 2.049, rounded to 2.05

thank you,

mark

 

[xanthym]

im having trouble setting my TI-83 Plus into "degree mode" so i can't seem to get the answers for these problems...im probably doing them wrong too

A material has an index of refraction of 1.75. What is the critical angle for this material?

Sin(critical angle)=1/n, n being the index of refraction
how would i set up the formula? (critical angle)= Sin(n) ?? I am so confused

and

The critical angle for cubic zirconium is 29.2º. What is the index of refraction?

so...Sin(29.2º)= 1/n?...

my answer for this question is 2.049, rounded to 2.05

thank you,

mark

In the following discussion, sin^-1 is the Inverse Sine function.
SOLUTION HINTS:
a) sin(θ_crit) = (1/n) :: ⇒ :: θ_crit = sin^-1(1/n) = sin^-1{1/(1.75)} = (34.85 deg)
b) sin(29.2 deg) = 1/n :: ⇒ :: n = 1/{sin(29.2 deg)] = (2.05)


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[OlderDan]

im having trouble setting my TI-83 Plus into "degree mode"

Press [MODE] and cursor down and right to the word Degree and hit [ENTER]

 

[mark9159]

thank you very much

 

[haydenbaird]

hahahhahah. are you in the BYU online homeschool thing too?