How Does Object Distance Affect Image Position in Refraction Problems?

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SUMMARY

The discussion focuses on determining the image position of an object placed at an infinite distance from a convex hemispherical surface of a glass rod with a diameter of 6.00 cm and a radius of 3.00 cm. The refractive index of the glass is 1.60. When the object is at infinity, the light rays become parallel, and the behavior of these rays upon striking the hemispherical surface can be analyzed using Snell's Law and standard equations for spherical lenses. The participants clarify the implications of placing the object at infinity and the resulting horizontal ray behavior.

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another refraction question??

The left end of a long glass rod 6.00 cm in diameter has a convex hemispherical surface 3.00 cm in radius. The refractive index of the glass is 1.60.

Determine the position of the image if an object is placed in air on the axis of the rod at the infinitely far distance to the left of the vertex of the curved end.


what does that mean? so is the distance of the object at infinity? I drew a picture for this problem, however the wording is confusing Maybe you might be able to tell me what they mean about the distance of the actual object?? Thankss!
 
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sghaussi said:
what does that mean? so is the distance of the object at infinity?

Putting the object at infinity just makes the light rays parallel and horizontal upon reaching the glass rod. Can you figure out what happens to a horizontal ray after striking the hemispherical glass surface at various positions?

Which equations are available to you? There are standard equations for spherical lenses/surfaces, but you can also derive the result from Snell's Law.
 
Ok, I just saw your other post. You can use the same equation I gave you there to do this problem.
 

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