Crossed Electric and Magnetic fields problem

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Homework Help Overview

The discussion revolves around a problem involving crossed electric and magnetic fields, specifically focusing on the net force acting on a charged particle moving in these fields. The subject area includes electromagnetism and vector addition of forces.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of the equation F=qE+qvB to determine the net force. There is a focus on the directionality of the forces involved, particularly how the electric and magnetic forces interact when they are perpendicular to each other.

Discussion Status

Participants are actively questioning the assumptions regarding the directions of the forces and how to correctly apply vector addition in this context. Some guidance has been offered regarding the need to consider the perpendicular nature of the forces when calculating the net force.

Contextual Notes

There is an emphasis on the importance of understanding the vector nature of forces, particularly since the electric force is parallel to the electric field while the magnetic force is perpendicular to both the magnetic field and the velocity of the charge.

futron
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"A magnetic field has a magnitude of 1.2 x 10-3 T, and an electric field has a magnitude of 5.1 x 10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 3.2 x 10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge."

Using the crossed magnetic and electric field equation, wouldn't the net force be F=qE+qvB? I resolved it to 0.01609N, which isn't the correct answer. Any ideas?

~Futron
 
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futron said:
"A magnetic field has a magnitude of 1.2 x 10-3 T, and an electric field has a magnitude of 5.1 x 10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 3.2 x 10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge."

Using the crossed magnetic and electric field equation, wouldn't the net force be F=qE+qvB? I resolved it to 0.01609N, which isn't the correct answer. Any ideas?

~Futron

Did you consider the direction of the forces? I did not check your answer, but that is a likely source of error.
 
Wouldn't Fnet be the sum if they are both pointed the same direction?

~Futron
 
futron said:
Wouldn't Fnet be the sum if they are both pointed the same direction?

~Futron

The fields are in the same direction. Electric force is parallel to the electric field. What about the magnetic force?
 
It is perpendicular relative to the magnetic field. How would I then calculate that into the Fnet equation? Thanks.

~Futron
 
futron said:
It is perpendicular relative to the magnetic field. How would I then calculate that into the Fnet equation? Thanks.

~Futron

Not only is it perpendicular to the magnetic field, it is perpendicular to the direction of the velocity of the charge. Of imporatance here is that since the electric force is parallel to the electric field, and the magnetic force is perpendicuar to that, the two forces involved are perpendicular. They must be added as vectors.
 
Got it. Thanks for your help!

~Futron
 

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