: really quick simplifying radical question

[xLaser]

hey, just a really quick question, any help wud be great,

is it possible to simplify this radical further?

p = sqrt root (6/70q^2)

thx in advance for help.

 

[OlderDan]

hey, just a really quick question, any help wud be great,

is it possible to simplify this radical further?

p = sqrt root (6/70q^2)

thx in advance for help.

Certainly. The ratio of two even numbers can always be simplified. Any time you have the square root of a square, you can simplify, though you do need to be careful. If q is any real number, then when you take the square root you cannot simply write q in the simplified expression, you need to write the absolute value of q. In most problems of this sort, variables are treated as positive quantities, but you need to check the context of the problem.

 

[xLaser]

the question stated q is greater than 0, therefore q is pos. but how would u simplify this since q does not have a number value?

 

[OlderDan]

the question stated q is greater than 0, therefore q is pos. but how would u simplify this since q does not have a number value?

If it were a number like 5, what would say about sqr root (5^2)? Change 5 to any other number, including fractions like 1/5. What must be true in general?

And remember that sqr root (a*b) = (sqr root(a))*(sqr root (b))

 

[DDS]

p=sqrt 3/35q^2

 

[OlderDan]

p=sqrt 3/35q^2

p=sqrt (3/35q^2). Keep going

 

[DDS]

older dan do u mind checking your private messages and reisitng some of my work on my posts as well..

please and thank u

 

[xLaser]

i got it

its sqrt105 /35q

 

[OlderDan]

i got it

its sqrt105 /35q

I don't think so. Where does 105 come from? You need to use parantheses to show what is in the square root and what is not.

 

[xLaser]

ok maybe u guys got orginial Question wrong.

it's actually p = sqrt root (6 / 70q^2)

so becomes sqrt 6 / sqrt 70 sqrt q^2

so becomes sqrt 6 / sqr 70 q

sqrt 6 * sqrt 70 / 70q

sqrt 420 / 70q

sqrt 105 / 35 q

 

[whozum]

there's a lot of algebra going wrong there.

$$\sqrt{\frac{6}{70q^2}}$$

$$\frac{\sqrt{6}}{\sqrt{70q^2}}$$

$$\frac{\sqrt{2}\sqrt{3}}{\sqrt{2}\sqrt{35}\sqrt{q^2}}$$

Do you follow that? That's one way to do it. Complete the process.

 

[xLaser]

yeah dude, ... ok so u get

sqrt 3 / sqrt 35 q

now u multiply by sqrt 35 / sqrt 35

and u get sqrt 105 / 35 q

..... lol...

 

[whozum]

You really should use parentheses.

 

[xLaser]

lol yeah i got to learn the things u guys use to write symbols out.