Some conceptual questions about light confused >_<

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Homework Help Overview

The discussion revolves around various conceptual questions related to light, including its behavior in different media, the nature of intensity, and the phenomenon of total internal reflection. Participants are exploring foundational aspects of optics and light properties as they prepare for an upcoming exam.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the relationship between wavelength and frequency in different media, questioning why violet light is not perceived as bright despite its higher frequency, and exploring the reasons behind the visibility of total internal reflection. There are inquiries about the definition of intensity and its relationship to energy and brightness.

Discussion Status

The conversation includes attempts to clarify misconceptions about intensity and its dependence on amplitude rather than frequency. Some participants have provided insights into the behavior of light in various contexts, while others are still seeking clarity on specific equations and concepts related to light intensity.

Contextual Notes

There are references to textbook definitions and equations, with some participants expressing confusion about the applicability of certain equations to light versus sound. The discussion reflects a mix of foundational knowledge and gaps in understanding that participants are working to address.

michaelw
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Hello
Im trying to understand light, I did it briefly inhigh school and I am writing the mcat this august... and I am quite confused

Is the wavelength of light at a specific frequency in water (n = 1.3) equal to the wavelength in a vacuum / 1.3?

Why is violet light not bright? Intensity is proportional to frequency ^2, so shouldn't violet be much more intense than red or yellow light?

Why can we see total internal reflection? Say in a diamond, light within the diamond hits an edge at the critical angle, causing the light to be reflected along the edges of the face.. why can we see this (the sparkle?).. no light is reaching our eyes, so why can we see the sparkle?

In my book it says "plane polarized light loses half its intensity.. plane polarized light is light having an electric field in just one direction". but why is it only reduced by half, if the electric fields of photons are in random directions? wouldn't you be blocking much more than 50% of the photons?

What exactly is intensity? is it just the brightness of the light? is it energy itself or proportional to it?

Please help me.. I've been reading this book for hours and I am still so confused with light
 
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michaelw said:
Is the wavelength of light at a specific frequency in water (n = 1.3) equal to the wavelength in a vacuum / 1.3?
Right. When light passes from air to water the frequency stays the same but the speed and wavelength are decreased by a factor of [itex]1/n[/itex].
Why is violet light not bright? Intensity is proportional to frequency ^2, so shouldn't violet be much more intense than red or yellow light?
Intensity is proportional to amplitude squared, not frequency.

Why can we see total internal reflection? Say in a diamond, light within the diamond hits an edge at the critical angle, causing the light to be reflected along the edges of the face.. why can we see this (the sparkle?).. no light is reaching our eyes, so why can we see the sparkle?
The light, of course, does reach your eyes. The internal reflection causes the facets to act as perfect mirrors; without such internal reflection, most of the light would "leak out" and be dispersed and not be reflected back so brightly.


In my book it says "plane polarized light loses half its intensity.. plane polarized light is light having an electric field in just one direction". but why is it only reduced by half, if the electric fields of photons are in random directions? wouldn't you be blocking much more than 50% of the photons?
If you think in terms of classical light, then the polarizer admits only the component parallel to its optic axis. (Look up the law of Malus.) For a randomly polarized incident beam, the transmitted beam ends up being half as intense. If you wish to think in terms of photons, you must view them quantum mechanically. A photon with polarization at an angle with respect to the polarizer still has a probability of being transmitted.

What exactly is intensity? is it just the brightness of the light? is it energy itself or proportional to it?
Think of the intensity as the power per unit area.
 
Doc Al said:
Right. When light passes from air to water the frequency stays the same but the speed and wavelength are decreased by a factor of [itex]1/n[/itex].

Intensity is proportional to amplitude squared, not frequency.

The equation in the book reads
I = (1/2)p(w^2)(A^2)v
where w = 2pi*frequency
 
michaelw said:
The equation in the book reads
I = (1/2)p(w^2)(A^2)v
where w = 2pi*frequency
Can you tell me what this equation is describing? What are p, w, A, & v?
 
I is intensity of a wave
p is density of medium
w is angular frequency
A is amplitude
v is wave velocity
 
That seems more a description of sound intensity in a medium, not light.
 
Doc Al said:
That seems more a description of sound intensity in a medium, not light.
ah youre right

would you happen to know the equation of intensity for light?
 
Because the intensity of light is a non-fundamental quantity. We may choose to definite it however we want. For example, in high-school you can learn that:

I = k/d^2

which is useful if you want to calculate the intensity of light at a certain distance relative to another. In planar wave form, you may use the Poyting vector and the average power of the electromagnetic waves, kind of similar to how we get the average power in electrical AC systems.

Lastly, if you really want it simple, the intensity of light is the amount of photons per second per unit area.

E = hf
Etotal = nhf (where n is the number of photons)
Power = nhf/second
Intensity = Power/area = (nhf/second)/area
 

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