What is the Differentiation Problem for the Function g(t)=t√(4-t)?

  • Context: Undergrad 
  • Thread starter Thread starter JoshHolloway
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Discussion Overview

The discussion revolves around the differentiation of the function g(t) = t√(4-t) for t < 3. Participants are attempting to express the derivative of the function and are sharing their approaches to writing it correctly, including the use of LaTeX formatting.

Discussion Character

  • Technical explanation, Homework-related

Main Points Raised

  • One participant provides the function g(t) and an initial attempt at its derivative g'(t), but the expression is not fully clarified.
  • Another participant expresses frustration with the formatting and suggests abandoning the attempt.
  • A third participant encourages the use of LaTeX for clarity and references another thread for additional context.
  • A later reply reiterates the function and provides a clearer LaTeX representation of the derivative, indicating a collaborative effort to refine the expression.

Areas of Agreement / Disagreement

There is no clear consensus on the differentiation process, as participants are at different stages of understanding and formatting the problem. Multiple approaches to presenting the derivative exist, and some confusion remains regarding the correct representation.

Contextual Notes

Participants have not fully resolved the differentiation steps, and there may be assumptions about the function's domain that are not explicitly stated.

JoshHolloway
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[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]
 
Last edited:
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I can not figure out how to use this text stuff, forget I said anything at all.
 
JoshHolloway said:
[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]

You got it Josh. Here's it is in LaTex. Just click on it to see the code:

[tex]g^{'}(t)=\frac{-t}{2\sqrt{4-t}}+\sqrt{4-t}[/tex]
 

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