What is the force exerted by an oak tree on a jogging person after collision?

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The force exerted by an oak tree on a jogging person after a collision is calculated to be 1584.59 Newtons. This calculation involves applying Newton's 2nd Law and the concept of impulse. The jogger, with a mass of 81.9 kg, collides with the tree at a speed of 4.7 m/s and rebounds at 4.2 m/s in the opposite direction. The time of contact during the collision is 46 milliseconds, which is crucial for determining the force exerted.

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If a healthy but somewhat direction impaired individual (mass = 81.9 kg) is jogging through the woods and runs straight into a large oak tree at 4.7 m/s. Rebound speed is measured at 4.2 m/s in the opposite direction. If the time of contact with the tree is 46 milliseconds, what is the magnitude of the force that the tree exerts on the jogger?
 
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What have you done? I suggest applying the acceleration definition ([itex]a = \frac{\Delta v}{\Delta t}[/itex]) directly into Newton's 2nd Law.
 
This is a simple application of an impulse. I = Force * time, and is also the change in momentum. Momentum is mass times velocity. Momentum before = 81.9 * 4.7 = 384.93. Momentum after=81.9*-4.2= -343.98. Impulse = 728.91 = force * time. Time=.46. 728.91=force * .46. Force is then equal to 1584.59 Newtons.
 

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