- #1
mathelord
what is the area bounded by the curve cos[x] within ranges of pi and 0
Calculating the Bounded Area of cos[x] from 0 to pi
- Thread starter mathelord
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Homework Help Overview
The discussion revolves around calculating the area bounded by the curve of cos[x] from 0 to π. Participants are exploring the implications of integration in this context.
Discussion Character
- Exploratory, Assumption checking
Approaches and Questions Raised
- Participants suggest using integration and drawing the graph of cos[x] to analyze the area. There are questions about whether the integration needs to be broken into parts due to the curve's behavior around the x-axis.
Discussion Status
The discussion is active, with various interpretations of the problem being explored. Some participants express concern about the phrasing of the original question and the clarity of the area being referenced. Guidance has been offered regarding the need for more information and the potential need to consider the curve's negative values.
Contextual Notes
There is uncertainty regarding the specifics of the area being calculated, particularly due to the behavior of the curve beyond π/2 and the phrasing of the original post. Participants are questioning the assumptions made in the problem statement.
- #2
Hurkyl
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Sounds like a good problem. Have you tried doing anything with it?
- #3
Nerro
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one word:"integration" use that ;)
- #4
Dr.Brain
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Draw the graph for cos[x] , and use integration from 0 to pie. After drawing the graph , see if you need to break up integration into two parts depending if the graph cuts the x-axis or not.
BJ
BJ
- #5
mathelord
what eventually becomes the answer
- #6
Hurkyl
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Why don't you work it out yourself? After all, it is your homework problem, is it not? If you just want to check your work, you could post your work...
- #7
mathelord
it's no h/work,i just posted it here.pls what will the answer be
- #8
HallsofIvy
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I hope this isn't homework! I'ts very badly phrased if it is. The curve y= cos(x) doesn't "bound" any area and, since y is negative for x> [tex]
\frac{\pi}{2}[/tex], it's not clear what area you are talking about.
How about giving us more information about exactly what question you are asking. How did this problem come up?
How about giving us more information about exactly what question you are asking. How did this problem come up?
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- #9
leright
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It could be 0 or 2, depending on the context of the problem. 
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