Solve Tangent Equation: Find A, B, & C for Ellipse

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Discussion Overview

The discussion revolves around finding the constants A, B, and C in the equation of an ellipse, specifically 4x² + y² + Ax + By + C = 0, under the conditions that the ellipse is tangent to the x-axis at the origin and passes through the point P(-1, 2).

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant suggests rewriting the equation to a more standard form for ellipses.
  • Another participant notes that since the ellipse must pass through the origin (0,0), this implies a specific value for C.
  • A participant explains that the tangency condition at the x-axis requires the normal to the ellipse at the origin to have no x-component, leading to a determination of A.
  • There is a reference to Dini's theorem, indicating a relationship between the gradient and the behavior of the ellipse at the tangency point.
  • One participant expresses confusion regarding how to determine the value of C, while another clarifies that substituting (0,0) into the equation directly yields C = 0.

Areas of Agreement / Disagreement

Participants generally agree on the approach to find C by substituting the origin into the equation, but there is some confusion regarding the implications of the tangency condition and the determination of A and B, indicating that the discussion remains unresolved in terms of a complete solution.

Contextual Notes

Some assumptions about the behavior of the ellipse at the tangency point and the implications of the gradient are not fully explored, leaving certain mathematical steps and relationships unresolved.

kidia
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Hi any idea on this please.

Find the values of constant A,B and C if the ellipse 4x^2 +y^2+Ax+By+C=0 is to be tangent to the x-axis at the origin and to pass through the point P(-1,2)
 
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what i would do first is to put the equation into a form more readable as far as ellipces aree concerned
 
You can also do it straight ahaid:

(1) The ellipse must pass through (0,0). What does this tell you about C?

(2) The ellipse must be tangent to the x-axis too. So the normal to the ellipse can not have an x-component. Recall that the gradient of a function is perpendicular to it's constant value curves. So the normal to the ellipse at the origin is given by the gradient of [tex]4x^2 +y^2+A x+B y+C[/tex] at (0,0). This gives us A.

(3) Just plug in the point P to find the remaining unknown B.
 
Dini's theorem: [tex]g(x_0, y_0)=0[/tex] and [tex]\nabla g|_{(x_0, y_0)} \neq \vec 0[/tex], then

[tex]\exists h(x) : g(x, h(x)) = 0[/tex] and

[tex]h'(x)=\frac {g_x} {g_y}[/tex]
 
I didn`t got u on getting constant Value C Timbuqtu
 
kidia said:
I didn`t got u on getting constant Value C Timbuqtu
Fill in the point (0,0) and you'll find immediately that c = 0.
If not, the ellipse wouldn't go through the origin.
 

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