First High & Low Tide in Harbor: Water Depth at 12am & 6pm

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Homework Help Overview

The discussion revolves around modeling the depth of the tide in a harbor using the equation y=21-5cos(πt/6), where y represents the water depth in feet and t is the time in hours. The focus is on determining the times of the first high tide and low tide within a 24-hour period, starting from midnight.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of the cosine function within the given model, questioning how its maximum and minimum values relate to the water depth. There is discussion about finding critical points through derivatives to identify high and low tides.

Discussion Status

The conversation is ongoing, with participants examining the mathematical properties of the cosine function and its impact on the water depth. Some guidance has been offered regarding the use of derivatives to find critical points, but no consensus has been reached on the specific times for high and low tides.

Contextual Notes

Participants are working within the constraints of the mathematical model provided and are considering the implications of the cosine function's range on the water depth. There is an emphasis on understanding the relationship between the model and the physical phenomenon of tides.

TonyC
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Suppose the depth of the tide in a certain harbor can be modeled by y=21-5cos pi t/6, whre y is the water depth in feet and t is the time in hours. Consider a day in which t=0 represents 12:00 midnight. For that day, when are the first high tide and the first low tide and what is the water depth at each time?
 
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You have:
[tex]-1 \leq \cos \alpha \leq 1[/tex]
So what can you say about the [tex]y = 21 - 5 \cos \frac{\pi t}{6}[/tex]
Viet Dao,
 
What are you looking for?
 
Okay, when y is minimum, that means:
[tex]5 \cos \frac{\pi t}{6}[/tex] is maximum.
So [tex]\cos \frac{\pi t}{6}[/tex] is maximum.
So y is minimum means that [tex]\cos \frac{\pi t}{6}[/tex] is maximum.
[tex]-1 \leq \cos \frac{\pi t}{6} \leq 1[/tex] so what t makes [tex]\cos \frac{\pi t}{6}[/tex] maximum?
Viet Dao,
 
you can take the first derivative and then find when it is 0 to tell you where your critical points are then use that to find the min and max
 

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