Is there a little bit more to the problem statement? What times are high tide and low tide? You need to know those times in order to get the time part of your equation correct...Veronica_Oles said:
How would the graph of ##y = 5\sin(30t) + 16## look in comparison to ##y = 5\sin(30(t - 3)) + 16##?Veronica_Oles said:
Wouldn't the second graph be shifted 3 units to the right?Mark44 said:
Yes. So the point (0, 16) on the first graph is shifted to the right by 3 (hours?) is now at (3, 16).Veronica_Oles said:
Why is it shifted? What in the original problem statement helps you to figure out when low tide is? You cannot answer this schoolwork problem without that information. And our help is limited by the accuracy of what you post about the Problem Statement.Veronica_Oles said:
The equation for finding the volume of an ocean is V = l*w*h, where V represents the volume, l is the length, w is the width, and h is the depth of the ocean.
To calculate the depth of an ocean, you will need the volume and the length and width of the ocean. You can rearrange the equation V = l*w*h to solve for h, which represents the depth. So, h = V/(l*w).
Yes, this equation can be used to calculate the volume of any ocean as long as you have the necessary measurements of length, width, and depth.
This equation is quite accurate in finding the volume of an ocean, as long as the measurements of length, width, and depth are precise. However, there may be other factors that can affect the accuracy, such as changes in the ocean's depth due to tides.
Yes, there are other equations and factors that can affect the accuracy of calculating the volume of an ocean. For example, the shape of the ocean floor, currents, and temperature can also impact the volume. It is important to gather as much data as possible and use multiple equations to get a more accurate measurement.