Solving a Homogeneous ODE: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around solving a homogeneous ordinary differential equation (ODE) of the form y' + 4xy - y^2 = 4x^2 - 7. Participants are exploring the methods to approach this problem and the implications of the homogeneous nature of the equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to manipulate the ODE by substituting v = y/x, leading to a transformed equation. Some participants suggest alternative substitutions and hint at techniques that may be relevant to the problem.

Discussion Status

The discussion is active, with participants providing hints and suggestions without revealing complete solutions. There is acknowledgment of the original poster's progress, and some participants are reflecting on the implications of university guidelines regarding independent work.

Contextual Notes

There are references to specific instructions from the University of Melbourne regarding independent problem-solving, which may influence the nature of the responses and hints provided in the discussion.

FeynmanIsMyHero
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Hi,

I'm having trouble with this ODE:

y' + 4xy - y^2 = 4x^2 - 7

=> y' = 4x^2 - 4xy + y^2 - 7
= (2x - y)^2 - 7

=> x(dv/dx) + v = (2x-vx)^2 - 7
= x^2(2-v)^2 - 7


I assume this ODE is of the homogeneous type, so I've substituted v=y/x and gotten thus far, but, what's the next step?
 
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FeynmanIsMyHero said:
Hi,

I'm having trouble with this ODE:

y' + 4xy - y^2 = 4x^2 - 7

=> y' = 4x^2 - 4xy + y^2 - 7
= (2x - y)^2 - 7




Try to replace 2x-y by v and solve for v. .

ehild
 
Hmm this looks exactly like one of the questions on my assignment. Don't know of you are from University of Melbourne but if you are then you are ignoring the explicit instruction that we're supposed to write up the solutions to the assignment independently.

In any case if you are from the same uni as I am then a hint that I can give you w/o actually telling you how to do the question is to go back to the problem sheets. There is a question which requires the same technique.

You are on the right track btw.
 
Last edited:
Thanks, I've figured it out now! :-p
 

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