How Much Air to Remove to Maintain Pressure When Temperature Increases?

Click For Summary

Homework Help Overview

The problem involves a tire filled with air at a specific temperature and pressure, and it seeks to determine the fraction of air that must be removed to maintain the original pressure when the temperature increases. The subject area relates to gas laws and thermodynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the ideal gas law and relationships between pressure, volume, and temperature. Some express confusion regarding the assumptions made, particularly about keeping temperature constant in certain calculations. Others attempt to derive the fraction of air to be removed using ratios of temperatures and pressures.

Discussion Status

The discussion is ongoing, with participants exploring different methods and clarifying concepts related to the problem. Some guidance has been offered regarding the application of gas laws, but there is no explicit consensus on the approach to take.

Contextual Notes

There is mention of using absolute temperatures and the ideal gas law, but participants are also grappling with the implications of changing temperature on pressure and volume. The original poster's attempts indicate a struggle with the mathematical relationships involved.

physicsss
Messages
319
Reaction score
0
A tire is filled with air at 10°C to a gauge pressure of 220 kPa. If the tire reaches a temperature of 30°C, what fraction of the original air must be removed if the original pressure of 220 kPa is to be maintained?

I tried finding the pressure at 30°C assuming volume stays the same using P1/T1=P2/T2 and got nowhere after that. Then I tried setting P to be equal and use the resulting formula of T1/V1=T2/V2 and got a percentage greater than 100%...
 
Physics news on Phys.org
First, get the final pressure (use all absolute terms) keeping volume constant. You are right with your first step.

Now keep the temperature constant and express the volume at initial pressure as a sum of initial volume and some increment. Now it is simple arithmetic.
 
I don't understand why you keep the temperature constant...can you explain some more?
 
physicsss said:
A tire is filled with air at 10°C to a gauge pressure of 220 kPa. If the tire reaches a temperature of 30°C, what fraction of the original air must be removed if the original pressure of 220 kPa is to be maintained?

I tried finding the pressure at 30°C assuming volume stays the same using P1/T1=P2/T2 and got nowhere after that. Then I tried setting P to be equal and use the resulting formula of T1/V1=T2/V2 and got a percentage greater than 100%...
So we have
n1T1=n2T2
so
n2/n1=T1/T2
n= amount of substance
T= temperature (absolute)
T1=(273.15+10)k=283.15k
T2=(273.15+30)k=303.15k
we desire to find
(n1-n2)/n1=1-n2/n1
fraction of air removed=1-n2/n1=1-T1/T2=1-(283.15k)/(303.15k)=6.6%
The general form for the ideal gas assumption for two sets of conditions is
(P1V1)/(n1T1)=(P2V2)/(n2T2)
P=pressure (absolute)
V=volume
n= amount of substance
T= temperature (absolute)
any that do not change may be droped
here pressure and volume we constant giving
n1T1=n2T2
 
Because you wanted to know the amount of air to be removed to obtain the initial pressure and at 30C temperature. Alternately, you can use the procedure given by lurflurf.
 

Similar threads

Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
16
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
9
Views
3K
Replies
2
Views
3K