How Do I Integrate sqrt(4x) + sqrt(4x) on the Interval 0 to 1?

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SUMMARY

The integration of the function sqrt(4x) + sqrt(4x) over the interval from 0 to 1 simplifies to 2 * sqrt(4x), which can be expressed as 4 * sqrt(x). The correct integral is calculated as follows: ∫(4 * sqrt(x)) dx from 0 to 1 results in (4/3) * x^(3/2) evaluated from 0 to 1, yielding a final answer of (4/3). The initial confusion stemmed from miscalculating the integral and not recognizing the simplification of the function.

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MathGnome
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Ok, I've been doing work for about 4 hours straight and I think my brain is fried. I know this is easy, it is just not working in my head.

Anyway, the problem is this:

Integrate the sqrt(4x) + sqrt(4x) on the interval 0 to 1

I get, (8^3/2)/3 + (8^3/2)/3 but apparently this is not right. I'm probably forgetting something I'll hit myself in the head for :cry: . Any help though?

Thx,
MathGnome
 
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