Kenetics problems no clue how to slove can someone help?

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Homework Help Overview

The discussion revolves around a kinematics problem involving a cab driver who accelerates and decelerates over a distance of 2.00 km. Participants are exploring the relationships between acceleration, deceleration, and distance traveled, while attempting to derive equations that represent the scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for three equations corresponding to the three unknowns in the problem. They consider various kinematic equations and question the role of initial and final velocities. Some express uncertainty about how to approach the problem without dealing with time directly.

Discussion Status

The discussion is ongoing, with participants offering equations and attempting to clarify the relationships between variables. There is a focus on deriving simultaneous equations and substituting variables to simplify the problem. Some participants express confusion about the setup and the implications of the equations being discussed.

Contextual Notes

Participants note that the only given quantity is the total distance of 2 km, and there is uncertainty regarding the final velocity at the end of the deceleration phase. The problem's constraints and the relationship between acceleration and deceleration magnitudes are also under consideration.

dparent
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ok so I am new at the whole college physics course and I am having problems with this ?

"A cab driver picks up a customer and delivers her 2.00 km away, on a straight route. The driver accelerates to the speed limit and, on reaching it, begins to decelerate at once. The magnitude of the deceleration is three times the magnitude of the acceleration. Find the lengths on the acceleration and deceleration phases."

looks like it should be and easy ? but I am drawing blanks can anyone help?
thanks
dan
 
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Can you think of 3 equations in 3 unknowns that correspond to this problem ? Such a system is solvable.
 
thats the prob

the question what right out of the book

the only quantity given was the 2 km i know that the initial velocity is 0 of course but that isn't of much help.

x=1/2(v0 +vf)t
x=v0t + 1/2at^2
 
You don't really have the luxury of dealing with time. Try using 2*a*d = vf2 - vi2, and remember that the sum of the distances in question is 2.00km for the third equation.
 
Last edited:
well i have 1 more equation i guess but I am not sure how to solve

vf^2 = v0^2 + 2ax

would the final velocity be 0? i guess i still am not sure how to solve could you use trial and error to figure the distance?
 
technically if you were to accelerate for .5 km and decel for 1.5 km it would give u ur 2km but ya... I am not very good in the physics department
 
dparent said:
well i have 1 more equation i guess but I am not sure how to solve

vf^2 = v0^2 + 2ax

would the final velocity be 0? i guess i still am not sure how to solve could you use trial and error to figure the distance?

You're not just solving one equation for one variable. You're finding three valid equations that together contain 3 unknowns as well as data from the problem. If x1 is the first distance and x2 is the second distance, then you should get the three simultaneous equations v2 = 2ax1, v2 = 6ax2, and x1 + x2 = 2.00 .
 
is it possible to solve with the 3 unknowns? I don't no I appreciate the time you spent trying to explain it to me.
thank you
 
You're only interested in x1 and x2. Try substituting like variables for their equivalents in other equations in order to get an equation that consists of only one variable (either x1 or x2), then solve it algebraically.
For example, since the v's are the same variable (the maximum velocity) in the equations above, we can write 2ax1 = 6ax2.
 
  • #10
k so i can get x1 alone by deviding by 2a so x1 = 3x2 I am looking for the 2 lengths still in km right of which the decel is 3 times the length of accel there for accel should be x1 + x2 = 2km .5 km? and decel should be 1.5km ? or am i just totally not getting what you are saying lol...?
 

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