Find equation in slope-intercept form

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Homework Help Overview

The discussion revolves around finding equations in slope-intercept form for various lines based on given points and conditions. The subject area includes linear equations and their properties, particularly focusing on slope and intercepts.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants present different scenarios for finding slope-intercept equations, including lines through specific points, horizontal lines, and lines that are perpendicular to others. Questions arise regarding the correctness of proposed equations based on substitution and interpretation of intercepts.

Discussion Status

Some participants offer guidance on testing equations by substituting points back into the equations. There is an ongoing exploration of the implications of horizontal lines and the conditions for perpendicular lines, with participants questioning the validity of each other's proposed equations.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the information they can provide or the methods they can use. There is a noted concern about the accuracy of y-intercepts in the context of the equations being discussed.

gillgill
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find equation in slope-intercept form for line through (-2, 3/4) and (2/3, 5/2)
does y=21/32x+33/16 seem right?

find equation in slope-intercept form for line through
Horizontal, through (8,7)
is it y=7??

find equation in slope-intercept form for line with x-intercept -2/3 and perpendicular to 2x-y=4
does y=-1/2x+1/3 right?
 
Last edited:
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You can test your first equation by substituting the points back into your equation.

The second equation y = 7 implies that for all x values the y value are 7. Does this seem right to you?

Your last equation cannot be right since the y-intercept is not the given one!
 
Last edited:
gillgill said:
find equation in slope-intercept form for line with x-intercept -2/3 and perpendicular to 2x-y=4
does y=-1/2x+1/3 right?

On this one, I got what you did, except the y-intercept of mine was negative. When I substituted -2/3 for x in y=-1/2x, i got 0=1/3 + b, therefore moving it to the other side would yield a negative...
 
ic...thanks...
 

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