Prove the Power Rule (calculus)

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Homework Help Overview

The problem involves proving the power rule for differentiation, specifically for the case where n is a rational number. The original poster seeks to demonstrate this using implicit differentiation from the equation y = x^(p/q), where p and q are integers and q > 0.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the validity of assuming the power rule for integer values of n. The original poster has differentiated the equation y^q = x^p implicitly and is exploring the next steps to isolate dy/dx.

Discussion Status

Some participants have provided guidance on manipulating the results from implicit differentiation and the relationship between y and x. There is an ongoing exploration of how to connect these expressions to reach the desired outcome.

Contextual Notes

The original poster must adhere to the stipulation of using implicit differentiation and the specific form of the equation provided. There is an emphasis on the assumption that p and q are integers with q being greater than zero.

mattxr250
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Ok guys, I'm new here and I need some help with a math problem...

The problem asks me to prove the power rule ---> d/dx[x^n] = nx^(n-1) for the case in which n is a ratioinal number...

the one stipulation is that I have to prove it using this method: write y=x^(p/q) in the form y^q = x^p and differentiate implicitly...assume that p and q are integers, where q>0.

Thanks for any help

Matt
 
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Are you allowed to assume that "d/dx[x^n] = nx^(n-1)" is true for n = an integer?

Have you differentiated "y^q = x^p" implicitly yet ?
 
yes I have and I came up with...


q(y^(q-1))(dy/dx) = p(x^(p-1))

but I'm stuck after I get here...i guess I could isolate dy/dx, but I'm not sure where to go from there...any help?
 
Well, do you know what y is?
 
if y = x^(p/q)
then
y' = (p/q)x^(p/q - 1)

Use the expression you got for for the implicit differentiatoin and the expression y^q = x^p and manipulatre them to end up with the required result, shown above.
 

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