Calculating Distance Traveled on Incline with Kinetic Friction

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The discussion focuses on calculating the distance a box travels up an incline before coming to rest, given an incline angle of 12.0° and a coefficient of kinetic friction of 0.180. The initial speed of the box is 2.40 m/s. Participants emphasize the importance of resolving forces acting on the box, including normal and tangential components, and suggest applying the work-energy theorem to relate the work done by friction to the change in mechanical energy. The frictional force acts against the motion, necessitating a thorough understanding of kinematics and energy principles.

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A box is sliding up an incline that makes an angle of 12.0° with respect to the horizontal. The coefficient of kinetic friction between the box and the surface of the incline is 0.180. The initial speed of the box at the bottom of the incline is 2.40 m/s. How far does the box travel along the incline before coming to rest?

I don't even know where to start. I'm guessing I should use kinematics, but where does the coefficient of kinetic friction and the angle fit into those?
 
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Resolve the forces acting on the box along and normal to the plane. normal components will balance ( write the equation0 and tengential components will accelerates the box( write the equation)
Remamper friction is in against the motion.
 
Have you tried an energy consideration? That is the work done by the frictional force should be equal to the change in the mechanical energy (it's kinetic and potential energy) of the box (this is called the work-energy theorem in Physics).
 

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