Why is the threshold for triplet production 4m0c^2?

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Discussion Overview

The discussion centers around the threshold energy required for triplet production in particle physics, specifically why it is set at 4m0c^2. Participants explore the underlying principles of energy and momentum conservation in this context.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant notes that the threshold for pair production is 2m0c^2 and questions why triplet production requires 4m0c^2.
  • Another participant explains that in photon interactions, electrons and positrons are produced in pairs due to conservation of electric charge, and that triplet production involves an additional particle that may have negligible momentum.
  • A detailed mathematical approach is presented, discussing conservation of energy and momentum, leading to the conclusion that the energy requirement for triplet production is 4m0c^2.
  • A subsequent participant requests clarification on a specific calculation step regarding the value of B, indicating a need for further explanation of the mathematical derivation.

Areas of Agreement / Disagreement

Participants express differing levels of understanding regarding the mathematical derivation of the threshold energy, indicating that the discussion remains unresolved in terms of clarity and consensus on the calculations involved.

Contextual Notes

The discussion includes complex mathematical expressions and assumptions about the conditions under which triplet production occurs, which may not be fully articulated or agreed upon by all participants.

coregis
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I can understand why the threshold for pair priduction is 2m0c^2. But why is the threshold for triplet production 4m0c^2? Thanks.
 
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If you're talking about photon to electron/positrons, then the reason is because electrons and positrons are always produced in pairs (conservation of electric charge, for instance). A triplet production includes one electron/positron that has so little momentum that it is missed.

The Feynman diagrams on page 4 of this paper will show what is going on:
http://arxiv.org/PS_cache/hep-ph/pdf/9909/9909323.pdf

Carl
 
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for triplet production conservation of energy is;

m(e)c2+hv=m(b+)c2+m(b-)c2+E(kinetic energy of participating electron on left side of equation)
Now assume that elctron was at rest so m(e)c2=_m(0)c2 and E= mc2 and also they (triplets)are more probabilistic to take equal E(K)
so above eq becomes
m(0)c2+hv=3mc2
and per conservation of momentum we have
hv/c=3mv=3mBc (B=v/c)

solving above 2 eq in B gives
(1-B2)1/2+3B=3 and that gives B=4/5
=give m=m(0)*5/3
now putting m value in momentum eq we get
hv=3*5/3*m(0)*4/5*c2=4m(0)c2
And this is due to conservation of momentum of photon as without third particle either e or nucleus this process is impossible as photon momentum is not conserved and as elctron rest mass is small it need more energy than pair production do, to physically this process to occur.
now i suppose that it will clear the threshold requirment
 
how did you find the value of B, i mean please show how B=4/5. I couldn't understand that step!
 

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