Calculus of parametric equations (finding surface area)

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SUMMARY

The discussion focuses on calculating the surface area of a curve defined by the parametric equations x=e^t sin(t) and y=e^t cos(t) for t in the range [0, π/2]. The surface area when revolved around the x-axis is given by the formula SA_x=2π∫[a to b] f(x)√(1+f'(x)²)dx, while the surface area around the y-axis is calculated using SA_y=2π∫[a to b] x√(1+f'(x)²)dx. The discussion emphasizes the need to identify f(x) and dx based on the provided parametric equations to apply these formulas correctly.

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  • Familiarity with integration techniques
  • Ability to differentiate functions
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  • Study the derivation of surface area formulas for parametric curves
  • Learn about the application of integration in calculating surface areas
  • Explore examples of surface area calculations for different curves
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Students and professionals in mathematics, particularly those studying calculus and surface area calculations, as well as educators looking for practical examples of parametric equations in action.

jrg_pz
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I was wondering what the surface area would be when the curve:

x=e^tsint,
and y=e^tcost where (t) is greater than or equal to (0) and (t) is less
or equal to pi divided by (2).
when it is revolved about
a) the x-axis
b) the y-axis (approximation with calc. (how?))
 
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jrg_pz said:
I was wondering what the surface area would be when the curve:

x=e^tsint,
and y=e^tcost where (t) is greater than or equal to (0) and (t) is less
or equal to pi divided by (2).
when it is revolved about
a) the x-axis
b) the y-axis (approximation with calc. (how?))

Around the x-axis you have:

[tex]\text{SA}_x=2\pi\int_{a}^{b}f(x)\left(\sqrt{1+f'(x)^2}\right)dx[/tex]

...the y-axis you have:

[tex]\text{SA}_y=2\pi\int_{a}^{b}x\left(\sqrt{1+f'(x)^2}\right)dx[/tex]

And I assume you can figure out what f(x) and dx are in terms of your parametric equations...
 

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