- #1
goohu
- 54
- 3
- Homework Statement
- check image
- Relevant Equations
- Gauss Law,
I do not have the solutions to this problem so I'm wondering if my attempt is correct.
My attempt at solution: We have two surfaces which we can calculate the area of. I think we can use gauss law to find the electric field and then integrate the E-field to find the electric potential.
So for the circular surface the area is pi*a^2. We get E*pi*a^2 = (1/e0)*ps.
For the spherical surface the area is (4*pi*a^2) / 2 = 2*pi*a^2. We get E*2*pi*a^2 = (1/e0)*ps
Next we solve for V by integrating E with regards to r with the limits being 0 to a.
Am I on the right track here?
My attempt at solution: We have two surfaces which we can calculate the area of. I think we can use gauss law to find the electric field and then integrate the E-field to find the electric potential.
So for the circular surface the area is pi*a^2. We get E*pi*a^2 = (1/e0)*ps.
For the spherical surface the area is (4*pi*a^2) / 2 = 2*pi*a^2. We get E*2*pi*a^2 = (1/e0)*ps
Next we solve for V by integrating E with regards to r with the limits being 0 to a.
Am I on the right track here?