Mass Ratios and Mutiple Proportions

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SUMMARY

The discussion centers on the "Law of Multiple Proportions," which states that when two elements combine in different ways, their mass ratios are small, whole number multiples. In the example provided, 66 grams of carbon (C) combines with oxygen (O) in carbon dioxide (CO2). The correct calculation for the mass of oxygen involved is 180 grams, derived from the atomic mass ratios of oxygen to carbon (32.00 to 12.01) and the stoichiometric relationships in the compound. The proper expression of this result in significant figures is 1.8 x 10^2 grams.

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The "Law of Multiple proportions" states that if two elements combine in different ways to form different substances, the mass ratios are small, whole number multiples of each other. Suppose that you have 66g of carbon combined with oxygen in carbon dioxide (CO2), how many grams of oxygen would you expect to be involved?

Well, I looked at the atomic mass ratios of oxygen to carbon, or 32.00 to 12.01. By dividing this I get 8/3, so I multiply (8/3)*66 g for 176 g of O? Is this correct?

Oh, exactly how would I express this in significant figures (or the proper form)? 1.8*10^2 g (if this is correct)?

Thanks.
 
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"66 grams" implies two significant figures. The ratio of carbon to oxygen in pure carbon dioxide is 1 atom carbon : 2 atoms oxygen . So,

[tex]\left( {\frac{{66g\;{\text{C}}}}{1}} \right)\left( {\frac{{1{\text{ mole C}}}}{{12g\;{\text{C}}}}} \right)\left( {\frac{{{\text{2}}\;{\text{moles O}}}}{{1{\text{ mole C}}}}} \right)\left( {\frac{{{\text{16}}g\;{\text{O}}}}{{1{\text{ mole O}}}}} \right) = 176g\;{\text{O}} \Rightarrow \boxed{{\text{180g}}\;{\text{O}}}[/tex]

Just 180 g is fine I think :wink:
 
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