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KYJelly
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An incomplete reaction of 12.125 g of propane proceeds as follows:
3 C3H8(g) + 14 O2(g) → 8 CO2(g) + 12 H2O(g) + C(s)
How many grams of solid carbon residue are produced as a product?
So, C3H8
C=3(12.01)=36.03 g/mol.
H=8(1.01) = 8.08 g/mol.
= 44.11 g/mol.
Therefore, 12.125 g C3H8 x (1 mol. C3H8/44.11g C3H8) = 0.2749 mol C3H8
Then, 0.2749 mol. C3H8 x (1 mol. C/3 mol. C3H8) = 0.09163 mol C
So, 0.09163 mol. C x (12.01 g C/ 1 mol. C) = 1.101 g C?
3 C3H8(g) + 14 O2(g) → 8 CO2(g) + 12 H2O(g) + C(s)
How many grams of solid carbon residue are produced as a product?
So, C3H8
C=3(12.01)=36.03 g/mol.
H=8(1.01) = 8.08 g/mol.
= 44.11 g/mol.
Therefore, 12.125 g C3H8 x (1 mol. C3H8/44.11g C3H8) = 0.2749 mol C3H8
Then, 0.2749 mol. C3H8 x (1 mol. C/3 mol. C3H8) = 0.09163 mol C
So, 0.09163 mol. C x (12.01 g C/ 1 mol. C) = 1.101 g C?