Why Did I Calculate the Cliff's Height Incorrectly?

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SUMMARY

The diver's horizontal velocity is 1.2 m/s, and the time of flight is 3.0 seconds. The correct calculations reveal that the horizontal distance from the cliff's base is 3.6 meters, while the height of the cliff is 44.1 meters. The formulas used were correct, but the values were mistakenly attributed to the wrong variables. The cliff height is determined using the formula y = -1/2gt², resulting in 44.1 meters, while the horizontal distance is calculated using Vxo = X/t, yielding 3.6 meters.

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need help please! what am i doing wrong??

A diver running 1.2 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3.0 s later. How high was the cliff and how far from its base did the diver hit the water?

so does v = 1.2 m/s and t=3 seconds
i used the formula Vxo=X/t so i did 1.2=x/3 so x = 3.6m for the first part of the question. for the second part of the question i used the formula y=-1/2gt^2 so i did y=(-1/2)(-9.8)(3^2) = 44.1m.
so i said that the cliff was 3.6m high and the base was 44.1m away. but i got it wrong. am i using the right formulas?
 
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You got the right formulas but you switched em, he landed 3.6 m away and the cliff was 44.1m high!
 
ohh! thank you so much! it didn't sound right that a cliff was 3.6m high and he hit the water at 44.1m! lol
 

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