Ranking the E-field from a graph alittle confused.

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SUMMARY

The discussion centers on ranking regions based on the magnitude of the x component of the electric field derived from the electric potential V as a function of x, as illustrated in Figures 24-27. The correct approach to determine the electric field is through the relationship E = -dV/dx, indicating that a steeper slope in the potential function corresponds to a greater electric field magnitude. The user initially attempted to rank the regions based on the length of the x distance and the area under the curve, both of which were incorrect. The correct ranking requires analyzing the slopes of the potential function.

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mr_coffee
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Figure 24-27 gives the electric potential V as a function of x.
Figure


(a) Rank the five regions according to the magnitude of the x component of the electric field within them, greatest first (use only the symbols > or =, for example 2=4>1=3>5).

I got the other 2 parts (b) and (c) right. What I thought was, the longer the space is in the x direction the bigger the magntude of the electric field. Which was wrong, i also tried to find the area under of the curve which was also wrong. When I tried to rank them from the area under the curve I got:
3>4=2>1>5
When i ranked them from the length fo the x distance, i got:
4>1=3=5>2

both wrong, what did i do wrong?
:bugeye:
 
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[tex]E=-\frac{dV(x)}{dx}[/tex]

That means that the greater the slope of [itex]V(x)[/itex], the greater the absolute value of [itex]E[/itex].
 
Awesome! thanks a lot!
 

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