Minimum Kinetic Friction for Inclined Block System

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SUMMARY

The discussion centers on calculating the minimum kinetic friction required to prevent acceleration in a system of two blocks connected by a string over a frictionless pulley on an inclined plane. The user correctly identified that setting the acceleration to zero in the formula a = (m2*g - m1*g*sin(θ) - μ*m1*g*cos(θ)) / (m1 + m2) is the first step. The challenge lies in isolating the variable for kinetic friction (μ) to find its minimum value. The user seeks further clarification and assistance in solving this equation.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with inclined plane physics
  • Knowledge of friction coefficients
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of forces acting on an inclined plane system
  • Learn how to isolate variables in physics equations
  • Explore the concept of static vs. kinetic friction
  • Review examples of block and pulley systems in physics textbooks
USEFUL FOR

Physics students, educators, and anyone interested in mechanics, particularly those studying forces on inclined planes and frictional forces in connected systems.

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I have a block conected to another block by a string in an inclined surface, with a frictionless pulley. Both blocks are the same weight so i already figure the acceleration of the object that its being pulled up.

What I don't know is how can I calculate the minimum kinetic friction that will keep the system from accelerating.

I tried setting the acceleration to zero for this formula:

[tex]a= 1\ frac{m2*g-m1*g*sin\theta - \mu*m1*g*cos\theta} {m1+m2} [\tex]<br /> <br /> after that i really don't get the answer. Please any sugestions.[/tex]
 
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Already answered in the other thread
 
thanks fermat
 

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