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Elysium
Oct4-05, 06:28 PM
Hi I'm new to this forum, I've seen it before but since I'm now taking physics courses at my university, I've decided to register.

I'm working on an assignment and I'm stuck on two or three questions. Some of them I've already solved, but there's one in particular that I'm not certain there's enough data given to solve it. Here it goes:

A book sits on a horizontal top of a car as the car accelerates horizontally from rest. If the static coefficient of friction between the car top and the book is 0.45, what is the maximum acceleration the car can have if the book is not to slip?
(a) 3.21 m/s2 (b) 3.76 m/s2 (c) 4.02 m/s2 (d) 4.41 m/s2

Now I can do certain friction problems, but I'm clueless on this one. I've tried to acquire the mass of the book form the static coefficient, but something tells me that I'm going in the wrong direction. Can anyone tell me what I should do to solve this problem? Thanx

Fermat
Oct4-05, 06:36 PM
There's enough data.

What is the friction between the book and the car's top ?
What is the accelerating force on the book ?
Apply Newton's 2nd law.

Elysium
Oct4-05, 06:49 PM
There's enough data.
Ok, that confirms it.

What is the friction between the book and the car's top ?
The friction cofficient constant is 0.45, so I gather this is a ratio based on the equation. Does it mean that a force required to push ths object is 9N for the book to weigh 20N?



What is the accelerating force on the book?
Since the book is in an initial state of equlibrium, I gather it's 0 or do you mean the 9N described above?


Apply Newton's 2nd law.
a = 9/2.04
= 4.41 m/s^2

It's one of the choices. I guess I solved it. But can you explain me about the coefficient more in detail? I feel like I'm doing this blindfolded. :uhh:

Elysium
Oct4-05, 07:47 PM
*bump*
Anyone can give me insight on this?

Doc Al
Oct4-05, 08:03 PM
The book is not in equilibrium.

Hint: The only horizontal force on the book is the static friction. So what's the maximum force on the book? (Any more and it will start to slip.) Then apply Newton's 2nd law to find the acceleration.

Elysium
Oct4-05, 08:51 PM
I got it, so the coefficient of static friction is just a ratio of the maximum friction force over the book's weight.

Fermat
Oct5-05, 01:05 AM
That's right.

You've got one eqn involving friction and the weight of the object.

Newton's 2nd law will give you the other eqn you need.