What is the propagation amplitude of a particle in QFT?

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SUMMARY

The propagation amplitude of a particle in Quantum Field Theory (QFT) is represented by the expression <0|phi(y)phi(x)|0>, which describes the transition of a particle from position x to position y. This is derived from the creation operator phi(x)|0> at position x and the operator <0|phi(y) at position y, indicating the presence of two particles in superposition. The discussion references Peskis and Schroeder's textbook, clarifying that the Heisenberg picture is utilized to understand these operators and their implications in particle propagation.

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Sombrero
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Hola everybody, this is my first visit to PF.
Can anyone help me please...my question is from QFT textbook
phi(x)|0> is creation of particle at position x, being in superposition of momenum states - - - - correct?
<0|phi(y) is birth of particle at position y. So if I consider both expressions i have two particles one born at position x, another particle born at position y.

Phi (x) Phi (y) already in Heisenberg picture.

Why <0|phi(y)phi(x)|0> why is this the propagation amplitude of particle from x to y as said in Peskis and Schroeders book? I have just two particles at x and y, One particle has been created at x, another at position y.

Gracias
 
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