How Do You Calculate the Correct Heading for an Airplane in Wind?

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Homework Help Overview

The problem involves calculating the correct heading for an airplane considering wind effects. The wind is blowing at a specific angle and speed, while the airplane has its own airspeed and needs to reach a destination defined in relation to its starting point.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to divide the vectors into x and y components and question the placement of angles in their diagrams. There is confusion regarding the definitions of the vectors involved, particularly the airplane's speed and its relation to the resultant vector.

Discussion Status

Participants are actively exploring different interpretations of the problem, with some suggesting the use of vector components and others questioning the definitions of the vectors. There is no explicit consensus, but guidance on vector decomposition has been provided.

Contextual Notes

Some participants express confusion about the roles of the vectors and the specific directions involved, indicating a need for clarification on the problem setup. There is mention of potential constraints related to the context of a test question.

byronsakic
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The wind is blowing N 75 degrees East at 96 km/h. A plane is flying with air speed 320 km/h. Find the heading the plane must have in order to get from A to B, if B is S40 degrees W of A. Include a diagram in your solution.

Alright, i am totally lost.
Could someone please maybe put on some tips or who may know what to do in finding the heading of the plane?
If you could also add a diagram it would be great because this is probably a test question for Geometry. XD

Thanks
 
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Last edited:
I get the same diagram, and angles the same.
 

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alright thanks, the A to B part confused me, because i didnt know which part would be A and B lol..
 
bah i am actually now confused in why the 320 km/h or planes speed is the resultant vector. Wouldnt 320 km/h be the S 40 DEGREE W vector in the third quadrant?

is there anyone else who would think there would be an alternative way ? XD

my first approach would to think to use the parallelogram theory.
 
Last edited:
If 320 km/h was the S 40 degree W vector, the wind would blow the airplane off-target. That is why the airplane must "overaim". I'm not sure what is meant by parallelogram theory, but you should divide the vectors into x and y components.
 
yes, so if i divided it into x and y components, i would be using cartesian vectors right? instead of geometric vectors
 

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