Apple123
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Here is the problem:
A 10.0-kg crate is pulled up a rought 20 degree incline by a 100-N force parallel to the incline. The initial speed of the crate is 1.5 m/s, and the coefficient of kinetic friction is 0.40. The crate is pulled a distance of 5.00m. Determine the work done by the:
1. Gravitational force
2. 100-n force
3. Change in KE of the crate
4. What is the speed after it is pulled 5.00m?
Here are my answers:
1. W=mgh=167.76 J
2. W=Fdcos(theta)=469.84J
3. KE=KE(f)-KE(i)= 302.085J
4. KE +W=KE(f) + PE(f)
v=7.916 m/s
Can anybody confirm these answers for me? I only feel half confident on them.
A 10.0-kg crate is pulled up a rought 20 degree incline by a 100-N force parallel to the incline. The initial speed of the crate is 1.5 m/s, and the coefficient of kinetic friction is 0.40. The crate is pulled a distance of 5.00m. Determine the work done by the:
1. Gravitational force
2. 100-n force
3. Change in KE of the crate
4. What is the speed after it is pulled 5.00m?
Here are my answers:
1. W=mgh=167.76 J
2. W=Fdcos(theta)=469.84J
3. KE=KE(f)-KE(i)= 302.085J
4. KE +W=KE(f) + PE(f)
v=7.916 m/s
Can anybody confirm these answers for me? I only feel half confident on them.