How do you get rid of the SIN() function to solve for x?

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Homework Help Overview

The original poster presents a problem involving the equation x*sin(x/2) - 18/pi = 0, expressing confusion about how to eliminate the sine function in order to solve for x. The context is centered around solving a transcendental equation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using Newton's method of approximation as a potential approach. Others inquire about the specifics of implementing this method and seek clarification on how to find an initial approximation.

Discussion Status

There is ongoing exploration of different methods to approach the problem, including graphical solutions and numerical methods. While some participants have shared insights on using Newton's method and graphing tools, there is no explicit consensus on a single method or solution yet.

Contextual Notes

Participants note that the function is periodic and will cross the x-axis multiple times, which may affect the choice of initial approximations for numerical methods. There is also mention of the need for a starting point in the approximation process, which remains an open question in the discussion.

r3dxP
i have x*sin(x/2) - 18/pi =0
and i need to solve for x..
how in the heck can i get rid of that sin() function? very confused.. any help will be appreicated..!
btw.. i need the answer ASAP! thanks a lot guys
 
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Can you use Newton's method of approximation ?
 
i guess you can, could u explain how i would do that? and give me the answer for x=? thanks
 
r3dxP said:
i guess you can, could u explain how i would do that? and give me the answer for x=? thanks
"[URL a good description[/URL] and an example of Newton's method of approximation.
You will have to find the initial starting point, x0 -- the firstapproximation -- yourself.

To do so, make up a table of x and f(x) values, where f(x) = x*sin(x/2) - 18/pi.
Use values of x like: pi, 2pi, 3pi, ... until you get a change in the sign of f(x). That means that the curve, f(x), has crossed the x-axis, and therefore has been, at some point, equal to zero between the two x-values that gave the change of sign.

Take half-way between the two x-values as your first approximation, x0. You can get a closer approximation to x0 if you are familiar with interpolation. But that might be a bit of overkill at this point.
 
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thanks a lot. i just figured out that i can just graph it with ti83plus, then go2 calc and use the 'zero' function :) thanks for the help
 
Even though you have the solution from the TI, here are additional comments that might be useful. Since this function is periodic, it will cross y=0 many times (see thumbnail). Newton's method works extremely well and converges very quickly on the solution, provided the starting guess of the solution is sufficiently close. Another option is bi-section, which is computationally much simpler, but takes longer to converge to the solution. Either method can easily be done w/ Excel.
 

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