Series Circuit Disconnected at Ammeter: Charge Flow?

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SUMMARY

When a series circuit is disconnected at the negative terminal of the ammeter, the current stops immediately. Although it takes a finite time for electrons to "know" there is no longer a potential difference, this propagation occurs at the speed of light, resulting in an almost instantaneous halt of current flow. Once the electrons are no longer under an accelerating potential, they quickly collide with ions, dissipating their kinetic energy. Consequently, the conductor becomes an equipotential, halting any charge buildup.

PREREQUISITES
  • Understanding of series circuits
  • Knowledge of ammeter functionality
  • Familiarity with electron behavior in conductive materials
  • Basic principles of electric potential and charge flow
NEXT STEPS
  • Research the speed of light and its implications in electrical circuits
  • Study the behavior of electrons in conductive materials under varying potentials
  • Explore the concept of equipotential in electrical engineering
  • Learn about the role of ammeters in measuring current in circuits
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Electrical engineers, physics students, and anyone interested in understanding the dynamics of current flow in series circuits.

mich_v87
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Hey i have a little question to ask... when a series circuit is broken (disconnected) at the negative terminal of the ammeter , does the charge flow around the circuit until it gets to the end of the line at the ammeter and then stop ? or does it stop at the moment when it's broken?
 
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The short answer is "yes, the current stops immediately!"

However, if you want to get into "overanalysis" mode then there is a little more to the story.

a) It takes a finite time for electrons in the circuit to "know" that there is no longer a potential difference. That information propagates at the speed of light and, typically, the time for the information to arrive is VERY small.

b) Once electrons are no longer subject to an accelerating potential, they are stopped, again almost immediately, because they collide with ions and give up their kinetic energy.

c) Even in the case of very low resistivity, any charge buildup will promptly be halted so that the conductor will become an equipotential.
 

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