Graphing a digit oscillating signal

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SUMMARY

This discussion focuses on graphing a digital oscillating signal, specifically addressing the concepts of pulse width and duty cycle. The duty cycle is defined as the ratio of pulse width to the total period, which is crucial for understanding the waveform. For a digital signal operating at 3.3V logic with a period of 1ms and a duty cycle of 25%, the graph should depict a rectangular waveform with specific voltage levels and time intervals. The frequency is calculated using the formula f = 1/T, where T is the period.

PREREQUISITES
  • Understanding of digital signal concepts
  • Familiarity with voltage levels in digital logic (e.g., 3.3V and 5V)
  • Knowledge of graphing techniques for waveforms
  • Basic understanding of frequency and period calculations
NEXT STEPS
  • Learn how to calculate pulse width from duty cycle and frequency
  • Explore graphing software tools for digital signal visualization
  • Study the effects of varying duty cycles on waveform shapes
  • Investigate the implications of different voltage levels in digital circuits
USEFUL FOR

Electronics engineers, signal processing specialists, and students learning about digital signal representation and analysis will benefit from this discussion.

Mr. Hiyasaki
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How would I go about graphing a digtal oscillating signal? I don't quite understand what a pulse width is, or rather how to find it given only the oscillation in Hz and a duty cycle. I understand that the duty cycle is the ratio of the pulse width over the total period, but i don't understand what the pulse width or the period is for a digital signal.
 
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Mr. Hiyasaki said:
How would I go about graphing a digtal oscillating signal? I don't quite understand what a pulse width is, or rather how to find it given only the oscillation in Hz and a duty cycle. I understand that the duty cycle is the ratio of the pulse width over the total period, but i don't understand what the pulse width or the period is for a digital signal.
On your graph, put time on the horizontal axis, and voltage on the vertical axis. If your digital signal is based on 3.3V logic, the top of the vertical axis will be about 4V. If it is 5V logic, use 5V as the top of the vertical axis. Then graph your digital signal versus time.
You end up with a rectangular waveform, or a square wave if the duty cycle is 50%. If the duty cycle is less than 50%, then the high time is less than the low time in the rectangular waveform. The period T is the time from one rising edge to the next rising edge, or from falling edge to next falling edge. The frequency is f = 1/T.
So let's say you are asked to graph a digital 3.3V signal with a period of 1ms and a duty cycle of 25%. You start at the origin of your graph with a rising edge from 0V to 3.3V, draw to the right from (0,3.3V) to (250us,3.3V), draw a falling edge to (250us,0V), and then draw the low part of the signal to (1ms,0V). Then you can repeat if you want to draw more than one cycle.
Makes sense?
 

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