Number of Wavelengths from Excited H Atom (n=9)

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Homework Help Overview

The discussion revolves around the emission of wavelengths from a hydrogen atom's electron that has been excited to the n = 9 energy level. Participants are exploring how many distinct wavelengths can be emitted as the electron transitions to lower energy levels.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to determine the number of distinct wavelengths emitted by considering the possible transitions from n = 9 to lower levels. There is discussion about the combinations of transitions and whether the initial assumption of 8 wavelengths is correct.

Discussion Status

Some participants have provided insights into the nature of the transitions and the potential for multiple combinations, while others have suggested a mathematical approach to calculate the number of wavelengths. The conversation is ongoing, with no consensus reached yet.

Contextual Notes

There is a focus on understanding the transitions and combinations involved in the emission process, with participants questioning their assumptions about the number of wavelengths and the calculations involved.

Pengwuino
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Assume that a hydrogen atom's electron has been excited to the n = 9 level. How many wavelengths of light can be emitted as this excited atom loses energy?

there's the question presented to me.

Now in all my wonderful glory, I enter "8" and boom, I am wrong. Just to be sure... i do 6, 7, 8, 9, and 10. None of them work. Then i start thinking... ok it can transfer from n=9 to n=8 to n=3 to n=1... but then that brings up an incredible number of combonations.

Am I right here with 8 or have i lost all comprehension of the H atom?
 
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You're right, there's a lot of combinations of "hops" the electron can take in going from n = 9 down to n = 1. But the number of distinct, individual "hops" is actually fairly small. You should be able to enumerate them quickly.
 
So shouldn't it be roughly a 8+7+6+5+4+3+2+1 deal?
 
If I correctly understand the question, you can get the number of wavelengths by:
[tex]n_{wavelengths} = \frac{n_{level} (n_{level} -1)}{2}[/tex]
 

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