Inf Series, Summations with k, k^2 to get Summation of k(k+1)

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Homework Help Overview

The discussion revolves around finding a formula for the summation of the expression k(k+1) from k=1 to n, utilizing known summation formulas for Ek and Ek^2. Participants are exploring algebraic simplifications and relationships between these summations.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to express the summation \(\sum_{k=1}^n k(k+1)\) in terms of known summation formulas. There are questions about starting the problem and how to simplify the resulting expressions.

Discussion Status

Several participants have provided insights into breaking down the expression into simpler components, such as separating k(k+1) into k^2 and k. There is an ongoing exploration of how to combine these summations effectively, with some participants expressing uncertainty about the next steps.

Contextual Notes

Some participants mention challenges with the format of the discussion, such as using LaTeX for mathematical expressions. There is also a note of potential misinterpretation of the assignment details, indicating a need for clarity in communication.

Natasha1
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As I don't know how to use this latex coding here it goes...

if I represent by E the sum of terms where k=1 and n is the unknown

I need to use the formulae for Ek and Ek^2 to obtain a formula for Ek(k+1), by simplifying the algebra as much as possible.

Can someone help with this please?
 
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Natasha1 said:
As I don't know how to use this latex coding here it goes...
if I represent by E the sum of terms where k=1 and n is the unknown
I need to use the formulae for Ek and Ek^2 to obtain a formula for Ek(k+1), by simplifying the algebra as much as possible.
Can someone help with this please?
Are you asking for:

[tex]\sum_{k=1}^nk\left(k+1\right)[/tex]

?

If so, note that k(k+1)=k2+k.
 
apmcavoy said:
Are you asking for:
[tex]\sum_{k=1}^nk\left(k+1\right)[/tex]
?
If so, note that k(k+1)=k2+k.

Yes I am asking exactly that :-).

Could someone start this problem, because I am stuck? Thank you :shy:
 
apmcavoy said:
Are you asking for:
[tex]\sum_{k=1}^nk\left(k+1\right)[/tex]
?
If so, note that k(k+1)=k2+k.

You have seen the last line of the above reply right?
So you have:
[tex]\sum_{k=1}^nk\left(k+1\right)=\sum_{k=1}^n k^2+\sum_{k=1}^nk[/tex]
that should take you off
 
pinodk said:
You have seen the last line of the above reply right?
So you have:
[tex]\sum_{k=1}^nk\left(k+1\right)=\sum_{k=1}^n k^2+\sum_{k=1}^nk[/tex]
that should take you off


Ok so now I get

= 1^2+1+2^2+2+3^3+3+...+n^2+n

and then what do I do?


Is the answer then

= n^2 + n
 
Last edited:
If I understand your assignment correctly, you already have the formulas for the two expressions

[tex]\sum_{k=1}^n k^2[/tex]
[tex]\sum_{k=1}^nk[/tex]

So just put a "+" between them :-) and simplify them even more if possible...

But being foreign and all, i could have misinterpreted what you wrote, so please don't hate me if that's the case ;-)
 

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