How Does UV Light Initiate Chlorine Atom Splitting in Chlorination?

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Discussion Overview

The discussion centers on the mechanism by which UV light initiates the splitting of chlorine atoms into free radicals during the chlorination process, particularly in the context of chlorination of methane. Participants explore the underlying physical and chemical principles involved, including bond cleavage and energy absorption.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants explain that UV light provides the energy necessary for the homolytic cleavage of the Cl-Cl bond, resulting in the formation of two Cl radicals.
  • One participant mentions that the energy from the photon causes the sigma bond to be cleaved, leading to the generation of free radicals.
  • Another viewpoint suggests that the vibration of the Cl2 molecule is excited until the bond is "ripped" apart, indicating a different perspective on the bond breaking process.
  • There is a reference to Einstein's equation E=hf, suggesting that the energy of the photons matches the energy required to excite the electrons in the Cl-Cl bond, facilitating the bond's disassociation.
  • One participant proposes that understanding this process may require knowledge of free energy diagrams and advanced topics in physics or physical chemistry.
  • A later reply elaborates on the nature of the sigma bond and how it can be cleaved homolytically, emphasizing the role of photonic energy in this excitation.

Areas of Agreement / Disagreement

Participants generally agree on the role of UV light in initiating the bond cleavage, but there are differing explanations regarding the exact mechanism and the nature of the bond breaking process. The discussion remains unresolved with multiple competing views on the specifics.

Contextual Notes

Some participants reference advanced concepts in physics and chemistry, indicating that a full understanding may depend on specific educational backgrounds or texts. There are also mentions of energy states and the nature of sigma bonds that may require further clarification.

Cheman
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Chlorination mechanism...

In chlorination, with chlroine gas and methane, why does the UV light cause the chlorine atom to split into free radicals? I know that it "supply the energy", but what actually happens?

Thanks. :wink:
 
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Yes, you form two Cl radicals. One Cl radical can then abstract a hydrogen atom from methane to make HCl and a methyl radical. The methyl radical can then combine with another Cl radical to make the product, chloromethane.
 
Well, Movies answered the question fairly well, but I think there is something with [tex]h\nu[/tex]; the energy in photon causes the sigma bond to be homolytically (just in the middle) cleaved, giving away two radicals, as Movies also wrote. The rest is very clear from his post.
 
Yes, chem_tr is right. I guess I glossed over how that actually happens. I have always thought of it as exciting the vibration of the Cl2 molecule until the Cl-Cl bond is essentially "ripped" apart.
 
Yeah I think it's to do with Eistien's E=hf and homolytic fission occurs in Cl2. The free radical is very reactive, and can therefore substitute a hydrogen from methane.
 
You should see this in the perspective of free energy diagram, if you wish to "know what happens." It should be given in your text.
 
Thats really quite an advanced question. If you want to know the real answer, you learn it in either third semester physics (modern physics) or second semester physical chemistry.

It has to do with the energy state of the electrons in Cl-Cl bond. In this case, it happens that the electrons in the sigma bond absorb light in the frequency of the UV region, because their energy states are matched by the energy of the photon, where E = hf. The excited electrons jump up to a higher energy state, which causes the bond to "break" and disassociate homolytically.
 
Thanks so-crates - could you please elaborate further on how the bond actually breaks?
 
As he said, a single sigma bond with two electrons can be cleaved homolytically, if each electron is a sigma bonding and sigma* antibonding orbital; in this case, the bond is homolytically broken. The photonic energy is very high to supply this excitation.
 

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