Thread: diff.eqn. help View Single Post

## diff.eqn. help

I need help figuring out the solution to this diff.eq.

y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1]

I have to show that:
y(x) + y(x) = 0 , x є [ -1, 1]

subject to:

y(1) + y(-1) = 0

y(1) + y(-1) = 2