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 P: 32 I need help figuring out the solution to this diff.eq. y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1] I have to show that: y(x) + y(x) = 0 , x є [ -1, 1] subject to: y(1) + y(-1) = 0 y(1) + y(-1) = 2 Thanks for any help you can give.