diff.eqn. help

jt316

I need help figuring out the solution to this diff.eq.

y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1]

I have to show that:
y``(x) + y(x) = 0 , x є [ -1, 1]

subject to:

y(1) + y(-1) = 0

y`(1) + y`(-1) = 2

Thanks for any help you can give.

jt316	diff.eqn. help Tweet I need help figuring out the solution to this diff.eq. y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-\| x – u \| ) y(u) du] , x є [ -1, 1] I have to show that: y``(x) + y(x) = 0 , x є [ -1, 1] subject to: y(1) + y(-1) = 0 y`(1) + y`(-1) = 2 Thanks for any help you can give.