I need help figuring out the solution to this diff.eq.
y(x) = x + (1/2)*∫(from u=1 to 1)[ ( 1 x – u  ) y(u) du] , x є [ 1, 1]
I have to show that:
y``(x) + y(x) = 0 , x є [ 1, 1]
subject to:
y(1) + y(1) = 0
y`(1) + y`(1) = 2
Thanks for any help you can give.
