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Apr25-07, 05:27 PM
setup help needed:apparent depth vs. actual depth
It depends on where you are looking from.
If you are directly above the light then, as you said i=90deg and the light goes straight out - the apparent depth is then just real_depth/n.
If you are standing on the side of the pool then just draw a triangle, and the real depth is the hypotenuse.
but if you go from the standpoint that the observer is @ the side of the pool, how do you find the apparent depth?