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neutrino
neutrino is offline
#5
Jul3-07, 03:31 PM
P: 2,048
Quote Quote by Dick View Post
The thing is that I think you might find this property useful for proving x=inf S.


I thought you were suggesting this...

x<(x+y)/2
y>(x+y)/2

Therefore x<(x+y)/2<y - this being a much shorter solution than what I had written down earlier. I'm not sure how (x+y)/2 relates to inf S.