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f(x) = [tex] 3 - \frac{4}{x-1}[/tex]
find [tex]f^{-1}[/tex]
state the domain of [tex]f^{-1}[/tex]
so finding the inverse would be:
x = [tex] 3 - \frac{4}{x-1}[/tex]
x² - x = 3x - 3 - 4
thus that's how i got the quadratic. Is it wrong?
EDIT: AHH sorry i want to find the domain of the inverse which is easy as it's the range of the original, whch is x >1. Still, is my inverse function correct?
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