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Finding Ranges of inverse functions
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thomas49th
#
11
Jun5-08, 01:32 PM
P: 656
y = 3 - 4/x-1
y(x-1) = 3x - 3 - 4
yx - y = 3x - 7
yx - 3x = y + 7
x(y-3) = y + 7
x = y+7/y-3
= x+7/x+3
is that right now?
Cheers :)